details

property	value
status	complete
benchmark	abaaaa-aaaaabaabaab.srs.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n142.star.cs.uiowa.edu
space	Wenzel_16

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.69036 seconds
cpu usage	7.72055
user time	7.40787
system time	0.312681
max virtual memory	1.8943476E7
max residence set size	339280.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(x1)))))) -> a(a(a(a(a(b(a(a(b(a(a(b(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(a(b(a(a(a(a(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(a(b(a(a(a(a(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(x))))) -> b(a(a(b(a(a(b(a(a(a(a(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(x))))) -> b(a(a(b(a(a(b(a(a(a(a(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(x))))) -> b(a(a(b(a(a(b(a(a(a(a(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 421, 422, 423, 424, 425, 426, 427, 428, 429, 430, 431, 432, 433, 434, 435, 436, 437, 438, 439, 440, 441, 442 Node 421 is start node and node 422 is final node. Those nodes are connected through the following edges: * 421 to 423 labelled b_1(0)* 422 to 422 labelled #_1(0)* 423 to 424 labelled a_1(0)* 424 to 425 labelled a_1(0)* 425 to 426 labelled b_1(0)* 426 to 427 labelled a_1(0)* 427 to 428 labelled a_1(0)* 428 to 429 labelled b_1(0)* 429 to 430 labelled a_1(0)* 429 to 433 labelled b_1(1)* 430 to 431 labelled a_1(0)* 430 to 433 labelled b_1(1)* 431 to 432 labelled a_1(0)* 431 to 433 labelled b_1(1)* 432 to 422 labelled a_1(0)* 432 to 433 labelled b_1(1)* 433 to 434 labelled a_1(1)* 434 to 435 labelled a_1(1)* 435 to 436 labelled b_1(1)* 436 to 437 labelled a_1(1)* 437 to 438 labelled a_1(1)* 438 to 439 labelled b_1(1)* 439 to 440 labelled a_1(1)* 439 to 433 labelled b_1(1)* 440 to 441 labelled a_1(1)* 440 to 433 labelled b_1(1)* 441 to 442 labelled a_1(1)* 441 to 433 labelled b_1(1)* 442 to 422 labelled a_1(1)* 442 to 433 labelled b_1(1) ---------------------------------------- (6) YES popout

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