details

property	value
status	complete
benchmark	abaababa-aababababaab.srs.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n151.star.cs.uiowa.edu
space	Wenzel_16

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.79477 seconds
cpu usage	7.64908
user time	7.31908
system time	0.329996
max virtual memory	1.9540728E7
max residence set size	316680.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(b(a(x1)))))))) -> a(a(b(a(b(a(b(a(b(a(a(b(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(x1)))))))) -> b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(a(b(a(x1)))))))) -> b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(a(b(x))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(x))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(a(b(x))))))) -> b(a(a(b(a(b(a(b(a(b(a(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 475, 476, 477, 478, 479, 480, 481, 482, 483, 484, 485, 486, 487, 488, 489, 490, 491, 492, 493, 494, 495, 496 Node 475 is start node and node 476 is final node. Those nodes are connected through the following edges: * 475 to 477 labelled b_1(0)* 476 to 476 labelled #_1(0)* 477 to 478 labelled a_1(0)* 478 to 479 labelled a_1(0)* 479 to 480 labelled b_1(0)* 480 to 481 labelled a_1(0)* 481 to 482 labelled b_1(0)* 482 to 483 labelled a_1(0)* 482 to 487 labelled b_1(1)* 483 to 484 labelled b_1(0)* 484 to 485 labelled a_1(0)* 484 to 487 labelled b_1(1)* 485 to 486 labelled b_1(0)* 486 to 476 labelled a_1(0)* 486 to 487 labelled b_1(1)* 487 to 488 labelled a_1(1)* 488 to 489 labelled a_1(1)* 489 to 490 labelled b_1(1)* 490 to 491 labelled a_1(1)* 491 to 492 labelled b_1(1)* 492 to 493 labelled a_1(1)* 492 to 487 labelled b_1(1)* 493 to 494 labelled b_1(1)* 494 to 495 labelled a_1(1)* 494 to 487 labelled b_1(1)* 495 to 496 labelled b_1(1)* 496 to 476 labelled a_1(1)* 496 to 487 labelled b_1(1) ---------------------------------------- (6) YES popout

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