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SRS Standard pair #487089742
details
property
value
status
complete
benchmark
abcbaaaa-aaaaabcbaaabcb.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n140.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.751 seconds
cpu usage
4.08418
user time
3.91278
system time
0.171404
max virtual memory
1.894428E7
max residence set size
315744.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(b(a(a(a(a(x1)))))))) -> a(a(a(a(a(b(c(b(a(a(a(b(c(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(c(b(a(x1)))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(c(b(a(x1)))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(c(b(x))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(c(b(x))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(c(b(x))))))) -> b(c(b(a(a(a(b(c(b(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 513, 514, 515, 516, 517, 518, 519, 520, 521, 522, 523, 524, 525, 526, 527, 528, 529, 530, 531, 532, 533, 534, 535, 536, 537, 538 Node 513 is start node and node 514 is final node. Those nodes are connected through the following edges: * 513 to 515 labelled b_1(0)* 514 to 514 labelled #_1(0)* 515 to 516 labelled c_1(0)* 516 to 517 labelled b_1(0)* 517 to 518 labelled a_1(0)* 518 to 519 labelled a_1(0)* 519 to 520 labelled a_1(0)* 520 to 521 labelled b_1(0)* 521 to 522 labelled c_1(0)* 522 to 523 labelled b_1(0)* 523 to 524 labelled a_1(0)* 523 to 527 labelled b_1(1)* 524 to 525 labelled a_1(0)* 524 to 527 labelled b_1(1)* 525 to 526 labelled a_1(0)* 525 to 527 labelled b_1(1)* 526 to 514 labelled a_1(0)* 526 to 527 labelled b_1(1)* 527 to 528 labelled c_1(1)* 528 to 529 labelled b_1(1)* 529 to 530 labelled a_1(1)* 530 to 531 labelled a_1(1)* 531 to 532 labelled a_1(1)* 532 to 533 labelled b_1(1)* 533 to 534 labelled c_1(1)* 534 to 535 labelled b_1(1)* 535 to 536 labelled a_1(1)* 535 to 527 labelled b_1(1)* 536 to 537 labelled a_1(1)* 536 to 527 labelled b_1(1)* 537 to 538 labelled a_1(1)* 537 to 527 labelled b_1(1)* 538 to 514 labelled a_1(1)* 538 to 527 labelled b_1(1) ---------------------------------------- (6) YES
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