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SRS Standard pair #487089778
details
property
value
status
complete
benchmark
aabbababa-abababaabbaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n144.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.67066 seconds
cpu usage
4.00333
user time
3.81419
system time
0.189141
max virtual memory
1.9008216E7
max residence set size
325156.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(b(a(b(a(b(a(x1))))))))) -> a(b(a(b(a(b(a(a(b(b(a(a(b(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(b(a(a(x1))))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(b(b(a(a(x1))))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(b(b(a(x)))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(b(a(x)))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(b(b(a(x)))))))) -> b(a(a(b(b(a(a(b(a(b(a(b(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 448, 449, 450, 451, 452, 453, 454, 455, 456, 457, 458, 459, 460, 461, 462, 463, 464, 465, 466, 467, 468, 469, 470, 471 Node 448 is start node and node 449 is final node. Those nodes are connected through the following edges: * 448 to 450 labelled b_1(0)* 449 to 449 labelled #_1(0)* 450 to 451 labelled a_1(0)* 451 to 452 labelled a_1(0)* 452 to 453 labelled b_1(0)* 453 to 454 labelled b_1(0)* 454 to 455 labelled a_1(0)* 455 to 456 labelled a_1(0)* 455 to 461 labelled b_1(1)* 456 to 457 labelled b_1(0)* 457 to 458 labelled a_1(0)* 457 to 461 labelled b_1(1)* 458 to 459 labelled b_1(0)* 459 to 460 labelled a_1(0)* 459 to 461 labelled b_1(1)* 460 to 449 labelled b_1(0)* 461 to 462 labelled a_1(1)* 462 to 463 labelled a_1(1)* 463 to 464 labelled b_1(1)* 464 to 465 labelled b_1(1)* 465 to 466 labelled a_1(1)* 466 to 467 labelled a_1(1)* 466 to 461 labelled b_1(1)* 467 to 468 labelled b_1(1)* 468 to 469 labelled a_1(1)* 468 to 461 labelled b_1(1)* 469 to 470 labelled b_1(1)* 470 to 471 labelled a_1(1)* 470 to 461 labelled b_1(1)* 471 to 449 labelled b_1(1) ---------------------------------------- (6) YES
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