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SRS Standard pair #487089802
details
property
value
status
complete
benchmark
abaaaa-aaaaabababaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n184.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.79173 seconds
cpu usage
3.98075
user time
3.77397
system time
0.206781
max virtual memory
1.8744356E7
max residence set size
283344.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(x1)))))) -> a(a(a(a(a(b(a(b(a(b(a(a(b(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(b(a(b(a(a(a(a(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(b(a(b(a(a(a(a(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(x))))) -> b(a(a(b(a(b(a(b(a(a(a(a(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(x))))) -> b(a(a(b(a(b(a(b(a(a(a(a(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(x))))) -> b(a(a(b(a(b(a(b(a(a(a(a(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 344, 345, 346, 347, 348, 349, 351, 352, 354, 356, 358, 360, 363, 381, 382, 383, 384, 385, 386, 387, 388, 389, 390, 391 Node 344 is start node and node 345 is final node. Those nodes are connected through the following edges: * 344 to 346 labelled b_1(0)* 345 to 345 labelled #_1(0)* 346 to 347 labelled a_1(0)* 347 to 348 labelled a_1(0)* 348 to 349 labelled b_1(0)* 349 to 351 labelled a_1(0)* 351 to 352 labelled b_1(0)* 352 to 354 labelled a_1(0)* 354 to 356 labelled b_1(0)* 356 to 358 labelled a_1(0)* 356 to 381 labelled b_1(1)* 358 to 360 labelled a_1(0)* 358 to 381 labelled b_1(1)* 360 to 363 labelled a_1(0)* 360 to 381 labelled b_1(1)* 363 to 345 labelled a_1(0)* 363 to 381 labelled b_1(1)* 381 to 382 labelled a_1(1)* 382 to 383 labelled a_1(1)* 383 to 384 labelled b_1(1)* 384 to 385 labelled a_1(1)* 385 to 386 labelled b_1(1)* 386 to 387 labelled a_1(1)* 387 to 388 labelled b_1(1)* 388 to 389 labelled a_1(1)* 388 to 381 labelled b_1(1)* 389 to 390 labelled a_1(1)* 389 to 381 labelled b_1(1)* 390 to 391 labelled a_1(1)* 390 to 381 labelled b_1(1)* 391 to 345 labelled a_1(1)* 391 to 381 labelled b_1(1) ---------------------------------------- (6) YES
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