details

property	value
status	complete
benchmark	acbabacba-abacbacbabac.srs.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n142.star.cs.uiowa.edu
space	Wenzel_16

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.62549 seconds
cpu usage	3.71921
user time	3.51783
system time	0.201381
max virtual memory	1.8877716E7
max residence set size	277472.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(c(b(a(b(a(c(b(a(x1))))))))) -> a(b(a(c(b(a(c(b(a(b(a(c(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(a(b(a(b(c(a(x1))))))))) -> c(a(b(a(b(c(a(b(c(a(b(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(c(a(b(a(b(c(a(x1))))))))) -> c(a(b(a(b(c(a(b(c(a(b(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(c(a(b(a(b(c(x)))))))) -> c(a(b(a(b(c(a(b(c(a(b(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(a(b(a(b(c(x)))))))) -> c(a(b(a(b(c(a(b(c(a(b(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(c(a(b(a(b(c(x)))))))) -> c(a(b(a(b(c(a(b(c(a(b(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 384, 385, 386, 387, 388, 389, 390, 391, 392, 393, 394, 395, 396, 397, 398, 399, 400, 401, 402, 403, 404, 405 Node 384 is start node and node 385 is final node. Those nodes are connected through the following edges: * 384 to 386 labelled c_1(0)* 385 to 385 labelled #_1(0)* 386 to 387 labelled a_1(0)* 387 to 388 labelled b_1(0)* 388 to 389 labelled a_1(0)* 389 to 390 labelled b_1(0)* 390 to 391 labelled c_1(0)* 391 to 392 labelled a_1(0)* 391 to 396 labelled c_1(1)* 392 to 393 labelled b_1(0)* 393 to 394 labelled c_1(0)* 394 to 395 labelled a_1(0)* 394 to 396 labelled c_1(1)* 395 to 385 labelled b_1(0)* 396 to 397 labelled a_1(1)* 397 to 398 labelled b_1(1)* 398 to 399 labelled a_1(1)* 399 to 400 labelled b_1(1)* 400 to 401 labelled c_1(1)* 401 to 402 labelled a_1(1)* 401 to 396 labelled c_1(1)* 402 to 403 labelled b_1(1)* 403 to 404 labelled c_1(1)* 404 to 405 labelled a_1(1)* 404 to 396 labelled c_1(1)* 405 to 385 labelled b_1(1) ---------------------------------------- (6) YES popout

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