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SRS Standard pair #487090060
details
property
value
status
complete
benchmark
abaaaa-aaaaabaabaabab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n022.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.6696 seconds
cpu usage
3.90514
user time
3.71934
system time
0.185798
max virtual memory
1.8876344E7
max residence set size
311464.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(x1)))))) -> a(a(a(a(a(b(a(a(b(a(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(a(x1)))))) -> b(a(b(a(a(b(a(a(b(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(a(x1)))))) -> b(a(b(a(a(b(a(a(b(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(x))))) -> b(a(b(a(a(b(a(a(b(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(x))))) -> b(a(b(a(a(b(a(a(b(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(x))))) -> b(a(b(a(a(b(a(a(b(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 385, 386, 387, 388, 389, 390, 391, 392, 393, 394, 395, 396, 397, 398, 425, 426, 428, 430, 432, 434, 436, 438, 440, 442, 444, 446 Node 385 is start node and node 386 is final node. Those nodes are connected through the following edges: * 385 to 387 labelled b_1(0)* 386 to 386 labelled #_1(0)* 387 to 388 labelled a_1(0)* 388 to 389 labelled b_1(0)* 389 to 390 labelled a_1(0)* 390 to 391 labelled a_1(0)* 391 to 392 labelled b_1(0)* 392 to 393 labelled a_1(0)* 393 to 394 labelled a_1(0)* 394 to 395 labelled b_1(0)* 395 to 396 labelled a_1(0)* 395 to 425 labelled b_1(1)* 396 to 397 labelled a_1(0)* 396 to 425 labelled b_1(1)* 397 to 398 labelled a_1(0)* 397 to 425 labelled b_1(1)* 398 to 386 labelled a_1(0)* 398 to 425 labelled b_1(1)* 425 to 426 labelled a_1(1)* 426 to 428 labelled b_1(1)* 428 to 430 labelled a_1(1)* 430 to 432 labelled a_1(1)* 432 to 434 labelled b_1(1)* 434 to 436 labelled a_1(1)* 436 to 438 labelled a_1(1)* 438 to 440 labelled b_1(1)* 440 to 442 labelled a_1(1)* 440 to 425 labelled b_1(1)* 442 to 444 labelled a_1(1)* 442 to 425 labelled b_1(1)* 444 to 446 labelled a_1(1)* 444 to 425 labelled b_1(1)* 446 to 386 labelled a_1(1)* 446 to 425 labelled b_1(1) ---------------------------------------- (6) YES
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