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SRS Standard pair #487090109
details
property
value
status
complete
benchmark
aabccaaaa-aaaaaabccaabcc.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n053.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
MultumNonMulta 20 June 2020 20G sparse
configuration
default
runtime (wallclock)
0.929477 seconds
cpu usage
2.46637
user time
2.18642
system time
0.279949
max virtual memory
2.5663088E7
max residence set size
483156.0
stage attributes
key
value
starexec-result
YES
output
YES After renaming modulo { a->0, b->1, c->2 }, it remains to prove termination of the 1-rule system { 0 0 1 2 2 0 0 0 0 -> 0 0 0 0 0 0 1 2 2 0 0 1 2 2 } The system was reversed. After renaming modulo { 0->0, 2->1, 1->2 }, it remains to prove termination of the 1-rule system { 0 0 0 0 1 1 2 0 0 -> 1 1 2 0 0 1 1 2 0 0 0 0 0 0 } Applying the dependency pairs transformation. After renaming modulo { (0,true)->0, (0,false)->1, (1,false)->2, (2,false)->3 }, it remains to prove termination of the 9-rule system { 0 1 1 1 2 2 3 1 1 -> 0 1 2 2 3 1 1 1 1 1 1 , 0 1 1 1 2 2 3 1 1 -> 0 2 2 3 1 1 1 1 1 1 , 0 1 1 1 2 2 3 1 1 -> 0 1 1 1 1 1 , 0 1 1 1 2 2 3 1 1 -> 0 1 1 1 1 , 0 1 1 1 2 2 3 1 1 -> 0 1 1 1 , 0 1 1 1 2 2 3 1 1 -> 0 1 1 , 0 1 1 1 2 2 3 1 1 -> 0 1 , 0 1 1 1 2 2 3 1 1 -> 0 , 1 1 1 1 2 2 3 1 1 ->= 2 2 3 1 1 2 2 3 1 1 1 1 1 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 10: 0 is interpreted by / \ | 1 0 1 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | \ / 1 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 0 | | 0 0 0 2 0 0 0 0 0 0 | | 0 0 0 0 1 0 0 0 0 0 | | 0 0 0 0 0 1 0 0 0 0 | | 0 0 1 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 1 0 0 0 0 0 0 1 | | 0 1 1 0 1 0 0 0 0 0 | \ / 2 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 1 0 0 0 | | 0 0 0 0 0 0 0 1 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | \ / 3 is interpreted by / \ | 1 0 0 0 0 0 0 0 0 0 | | 0 1 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 1 0 0 0 0 1 0 | | 0 0 0 0 0 0 0 0 0 0 | | 0 0 0 0 0 0 0 0 0 0 | \ / After renaming modulo { 1->0, 2->1, 3->2 }, it remains to prove termination of the 1-rule system { 0 0 0 0 1 1 2 0 0 ->= 1 1 2 0 0 1 1 2 0 0 0 0 0 0 } The system is trivially terminating.
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