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SRS Standard pair #487090396
details
property
value
status
complete
benchmark
abaababababa-aabababababaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n022.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.65114 seconds
cpu usage
3.84887
user time
3.68925
system time
0.159614
max virtual memory
1.9010044E7
max residence set size
311280.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(b(a(b(a(b(a(x1)))))))))))) -> a(a(b(a(b(a(b(a(b(a(b(a(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(b(a(a(b(a(x1)))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(b(a(b(a(a(b(a(x1)))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(b(a(b(a(a(b(x))))))))))) -> b(a(a(b(a(b(a(b(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 585, 586, 587, 588, 589, 590, 591, 592, 593, 594, 595, 596, 597, 598, 599, 600, 601, 602, 603, 604, 605, 606, 607, 608, 609, 610 Node 585 is start node and node 586 is final node. Those nodes are connected through the following edges: * 585 to 587 labelled b_1(0)* 586 to 586 labelled #_1(0)* 587 to 588 labelled a_1(0)* 588 to 589 labelled a_1(0)* 589 to 590 labelled b_1(0)* 590 to 591 labelled a_1(0)* 590 to 599 labelled b_1(1)* 591 to 592 labelled b_1(0)* 592 to 593 labelled a_1(0)* 592 to 599 labelled b_1(1)* 593 to 594 labelled b_1(0)* 594 to 595 labelled a_1(0)* 594 to 599 labelled b_1(1)* 595 to 596 labelled b_1(0)* 596 to 597 labelled a_1(0)* 596 to 599 labelled b_1(1)* 597 to 598 labelled b_1(0)* 598 to 586 labelled a_1(0)* 598 to 599 labelled b_1(1)* 599 to 600 labelled a_1(1)* 600 to 601 labelled a_1(1)* 601 to 602 labelled b_1(1)* 602 to 603 labelled a_1(1)* 602 to 599 labelled b_1(1)* 603 to 604 labelled b_1(1)* 604 to 605 labelled a_1(1)* 604 to 599 labelled b_1(1)* 605 to 606 labelled b_1(1)* 606 to 607 labelled a_1(1)* 606 to 599 labelled b_1(1)* 607 to 608 labelled b_1(1)* 608 to 609 labelled a_1(1)* 608 to 599 labelled b_1(1)* 609 to 610 labelled b_1(1)* 610 to 586 labelled a_1(1)* 610 to 599 labelled b_1(1) ---------------------------------------- (6) YES
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