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SRS Standard pair #487090522
details
property
value
status
complete
benchmark
abaabaaaaa-aaaaaabaabaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n151.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.77251 seconds
cpu usage
4.44678
user time
4.25625
system time
0.190534
max virtual memory
1.9275272E7
max residence set size
386060.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(b(a(a(a(a(a(x1)))))))))) -> a(a(a(a(a(a(b(a(a(b(a(a(b(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(a(a(b(a(x1)))))))))) -> b(a(a(b(a(a(b(a(a(a(a(a(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(b(a(a(b(a(x1)))))))))) -> b(a(a(b(a(a(b(a(a(a(a(a(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(b(a(a(b(x))))))))) -> b(a(a(b(a(a(b(a(a(a(a(a(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(a(a(b(x))))))))) -> b(a(a(b(a(a(b(a(a(a(a(a(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(b(a(a(b(x))))))))) -> b(a(a(b(a(a(b(a(a(a(a(a(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 566, 567, 568, 569, 570, 571, 572, 573, 574, 575, 576, 577, 578, 579, 580, 581, 582, 583, 584, 585, 586, 587, 588, 589 Node 566 is start node and node 567 is final node. Those nodes are connected through the following edges: * 566 to 568 labelled b_1(0)* 567 to 567 labelled #_1(0)* 568 to 569 labelled a_1(0)* 569 to 570 labelled a_1(0)* 570 to 571 labelled b_1(0)* 571 to 572 labelled a_1(0)* 572 to 573 labelled a_1(0)* 573 to 574 labelled b_1(0)* 574 to 575 labelled a_1(0)* 574 to 579 labelled b_1(1)* 575 to 576 labelled a_1(0)* 575 to 579 labelled b_1(1)* 576 to 577 labelled a_1(0)* 576 to 579 labelled b_1(1)* 577 to 578 labelled a_1(0)* 577 to 579 labelled b_1(1)* 578 to 567 labelled a_1(0)* 578 to 579 labelled b_1(1)* 579 to 580 labelled a_1(1)* 580 to 581 labelled a_1(1)* 581 to 582 labelled b_1(1)* 582 to 583 labelled a_1(1)* 583 to 584 labelled a_1(1)* 584 to 585 labelled b_1(1)* 585 to 586 labelled a_1(1)* 585 to 579 labelled b_1(1)* 586 to 587 labelled a_1(1)* 586 to 579 labelled b_1(1)* 587 to 588 labelled a_1(1)* 587 to 579 labelled b_1(1)* 588 to 589 labelled a_1(1)* 588 to 579 labelled b_1(1)* 589 to 567 labelled a_1(1)* 589 to 579 labelled b_1(1) ---------------------------------------- (6) YES
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