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SRS Standard pair #487090666
details
property
value
status
complete
benchmark
ababaababa-aababababaabab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n141.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.70113 seconds
cpu usage
3.94383
user time
3.78407
system time
0.159767
max virtual memory
1.9076832E7
max residence set size
302952.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(x1)))))))))) -> a(a(b(a(b(a(b(a(b(a(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(x1)))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(a(b(a(b(a(x1)))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(a(b(a(b(x))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(x))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(a(b(a(b(x))))))))) -> b(a(b(a(a(b(a(b(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 560, 561, 562, 563, 564, 565, 566, 567, 568, 569, 570, 571, 572, 573, 574, 575, 576, 577, 578, 579, 580, 581, 582, 583, 584, 585 Node 560 is start node and node 561 is final node. Those nodes are connected through the following edges: * 560 to 562 labelled b_1(0)* 561 to 561 labelled #_1(0)* 562 to 563 labelled a_1(0)* 563 to 564 labelled b_1(0)* 564 to 565 labelled a_1(0)* 565 to 566 labelled a_1(0)* 566 to 567 labelled b_1(0)* 567 to 568 labelled a_1(0)* 568 to 569 labelled b_1(0)* 569 to 570 labelled a_1(0)* 569 to 574 labelled b_1(1)* 570 to 571 labelled b_1(0)* 571 to 572 labelled a_1(0)* 571 to 574 labelled b_1(1)* 572 to 573 labelled b_1(0)* 573 to 561 labelled a_1(0)* 573 to 574 labelled b_1(1)* 574 to 575 labelled a_1(1)* 575 to 576 labelled b_1(1)* 576 to 577 labelled a_1(1)* 577 to 578 labelled a_1(1)* 578 to 579 labelled b_1(1)* 579 to 580 labelled a_1(1)* 580 to 581 labelled b_1(1)* 581 to 582 labelled a_1(1)* 581 to 574 labelled b_1(1)* 582 to 583 labelled b_1(1)* 583 to 584 labelled a_1(1)* 583 to 574 labelled b_1(1)* 584 to 585 labelled b_1(1)* 585 to 561 labelled a_1(1)* 585 to 574 labelled b_1(1) ---------------------------------------- (6) YES
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