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SRS Standard pair #487090934
details
property
value
status
complete
benchmark
10.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n184.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
42.1265 seconds
cpu usage
164.163
user time
161.632
system time
2.53083
max virtual memory
1.1840372E7
max residence set size
101928.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(b(b(x1))) -> b(b(a(a(x1)))) a(b(a(x1))) -> b(b(x1)) Proof: DP Processor: DPs: a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) TRS: a(b(b(x1))) -> b(b(a(a(x1)))) a(b(a(x1))) -> b(b(x1)) Matrix Interpretation Processor: dim=4 interpretation: [0 0 0 0] [0 0 1 0] [a](x0) = [1 0 0 1]x0 [0 0 0 1] , [0 1 0 0] [0] [0 0 0 0] [0] [b](x0) = [0 0 0 1]x0 + [0] [0 0 1 0] [1], [a#](x0) = [0 0 0 1]x0 orientation: a#(b(b(x1))) = [0 0 0 1]x1 + [1] >= [0 0 0 1]x1 = a#(x1) a#(b(b(x1))) = [0 0 0 1]x1 + [1] >= [0 0 0 1]x1 = a#(a(x1)) [0 0 0 0] [0] [0 0 0 0] [0] [0 0 1 0] [1] [0 0 0 0] [0] a(b(b(x1))) = [0 0 0 1]x1 + [1] >= [0 0 0 1]x1 + [1] = b(b(a(a(x1)))) [0 0 0 1] [1] [0 0 0 1] [1] [0 0 0 0] [0] [0 0 0 0] [0] [0 0 0 1] [0] [0 0 0 0] [0] a(b(a(x1))) = [1 0 1 1]x1 + [1] >= [0 0 1 0]x1 + [1] = b(b(x1)) [1 0 0 1] [1] [0 0 0 1] [1] problem: DPs: TRS: a(b(b(x1))) -> b(b(a(a(x1)))) a(b(a(x1))) -> b(b(x1)) Qed
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