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SRS Standard pair #487090982
details
property
value
status
complete
benchmark
multum3.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n151.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
43.215 seconds
cpu usage
168.966
user time
166.243
system time
2.72384
max virtual memory
1.163928E7
max residence set size
106100.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(a(b(x1))) -> b(b(a(a(x1)))) b(a(b(x1))) -> a(a(a(a(x1)))) Proof: String Reversal Processor: b(a(a(x1))) -> a(a(b(b(x1)))) b(a(b(x1))) -> a(a(a(a(x1)))) DP Processor: DPs: b#(a(a(x1))) -> b#(x1) b#(a(a(x1))) -> b#(b(x1)) TRS: b(a(a(x1))) -> a(a(b(b(x1)))) b(a(b(x1))) -> a(a(a(a(x1)))) Arctic Interpretation Processor: dimension: 2 usable rules: b(a(a(x1))) -> a(a(b(b(x1)))) b(a(b(x1))) -> a(a(a(a(x1)))) interpretation: [-& 0 ] [1] [a](x0) = [2 -&]x0 + [1], [0 2 ] [3 ] [b](x0) = [-& 0 ]x0 + [-&], [b#](x0) = [-& 1 ]x0 + [0] orientation: b#(a(a(x1))) = [-& 3 ]x1 + [4] >= [-& 1 ]x1 + [0] = b#(x1) b#(a(a(x1))) = [-& 3 ]x1 + [4] >= [-& 1 ]x1 + [0] = b#(b(x1)) [2 4 ] [5] [2 4 ] [5] b(a(a(x1))) = [-& 2 ]x1 + [3] >= [-& 2 ]x1 + [3] = a(a(b(b(x1)))) [4 6] [7] [4 -&] [3] b(a(b(x1))) = [2 4]x1 + [5] >= [-& 4 ]x1 + [5] = a(a(a(a(x1)))) problem: DPs: TRS: b(a(a(x1))) -> a(a(b(b(x1)))) b(a(b(x1))) -> a(a(a(a(x1)))) Qed
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