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SRS Standard pair #487091072
details
property
value
status
complete
benchmark
multum5.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n139.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.5973 seconds
cpu usage
5.2522
user time
4.51611
system time
0.736083
max virtual memory
5919672.0
max residence set size
72800.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(a(a(b(x1)))) -> b(a(a(a(x1)))) b(b(x1)) -> a(b(a(b(x1)))) Proof: String Reversal Processor: b(a(a(a(x1)))) -> a(a(a(b(x1)))) b(b(x1)) -> b(a(b(a(x1)))) Matrix Interpretation Processor: dim=4 interpretation: [1 0 0 0] [0 0 0 1] [a](x0) = [0 1 0 0]x0 [0 0 1 0] , [1 0 0 1] [0] [0 0 0 0] [0] [b](x0) = [0 0 0 0]x0 + [0] [0 0 1 0] [1] orientation: [1 0 0 1] [0] [1 0 0 1] [0] [0 0 0 0] [0] [0 0 0 0] [0] b(a(a(a(x1)))) = [0 0 0 0]x1 + [0] >= [0 0 0 0]x1 + [0] = a(a(a(b(x1)))) [0 0 1 0] [1] [0 0 1 0] [1] [1 0 1 1] [1] [1 0 1 0] [0] [0 0 0 0] [0] [0 0 0 0] [0] b(b(x1)) = [0 0 0 0]x1 + [0] >= [0 0 0 0]x1 + [0] = b(a(b(a(x1)))) [0 0 0 0] [1] [0 0 0 0] [1] problem: b(a(a(a(x1)))) -> a(a(a(b(x1)))) KBO Processor: weight function: w0 = 1 w(a) = 1 w(b) = 0 precedence: b > a problem: Qed
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