SRS Standard pair #487091105

details

property	value
status	complete
benchmark	z067.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n141.star.cs.uiowa.edu
space	Zantema_04

run statistics

property	value
solver	MultumNonMulta 20 June 2020 20G sparse
configuration	default
runtime (wallclock)	0.483477 seconds
cpu usage	0.937929
user time	0.749692
system time	0.188237
max virtual memory	113188.0
max residence set size	184228.0

stage attributes

key	value
starexec-result	YES

output

YES

After renaming modulo { P->0, Q->1, p->2, q->3 }, 
it remains to prove termination of the 9-rule system
{ 0 -> 1 1 2 ,
  2 2 -> 3 3 ,
  2 1 1 -> 1 1 2 ,
  1 2 3 -> 3 2 1 ,
  3 3 2 -> 2 3 3 ,
  3 1 -> ,
  1 3 -> ,
  2 0 -> ,
  0 2 -> }


The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 2:

0 is interpreted by
 /   \
| 1 1 |
| 0 1 |
 \   /
1 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /
2 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /
3 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /

After renaming modulo { 2->0, 3->1, 1->2 }, 
it remains to prove termination of the 6-rule system
{ 0 0 -> 1 1 ,
  0 2 2 -> 2 2 0 ,
  2 0 1 -> 1 0 2 ,
  1 1 0 -> 0 1 1 ,
  1 2 -> ,
  2 1 -> }


The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 2:

0 is interpreted by
 /   \
| 1 1 |
| 0 1 |
 \   /
1 is interpreted by
 /   \
| 1 1 |
| 0 1 |
 \   /
2 is interpreted by
 /   \
| 1 1 |
| 0 1 |
 \   /

After renaming modulo { 0->0, 1->1, 2->2 }, 
it remains to prove termination of the 4-rule system
{ 0 0 -> 1 1 ,
  0 2 2 -> 2 2 0 ,
  2 0 1 -> 1 0 2 ,
  1 1 0 -> 0 1 1 }


The system was filtered by the following matrix interpretation
of type E_J with J = {1,...,2} and dimension 2:

0 is interpreted by
 /   \
| 1 1 |
| 0 1 |
 \   /
1 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /
2 is interpreted by
 /   \
| 1 0 |
| 0 1 |
 \   /

After renaming modulo { 0->0, 2->1, 1->2 }, 
it remains to prove termination of the 3-rule system
{ 0 1 1 -> 1 1 0 ,
  1 0 2 -> 2 0 1 ,
  2 2 0 -> 0 2 2 }

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