details

property	value
status	complete
benchmark	z066.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n022.star.cs.uiowa.edu
space	Zantema_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	4.65502 seconds
cpu usage	14.9986
user time	14.2706
system time	0.728038
max virtual memory	9.9600508E7
max residence set size	1887316.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 22 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 10 ms] (6) QTRS (7) QTRSRRRProof [EQUIVALENT, 1 ms] (8) QTRS (9) DependencyPairsProof [EQUIVALENT, 19 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 36 ms] (12) QDP (13) DependencyGraphProof [EQUIVALENT, 0 ms] (14) AND (15) QDP (16) MRRProof [EQUIVALENT, 19 ms] (17) QDP (18) DependencyGraphProof [EQUIVALENT, 0 ms] (19) TRUE (20) QDP (21) MRRProof [EQUIVALENT, 19 ms] (22) QDP (23) DependencyGraphProof [EQUIVALENT, 0 ms] (24) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(x1))) -> c(b(a(x1))) C(B(A(x1))) -> A(B(C(x1))) b(a(C(x1))) -> C(a(b(x1))) c(A(B(x1))) -> B(A(c(x1))) A(c(b(x1))) -> b(c(A(x1))) B(C(a(x1))) -> a(C(B(x1))) a(A(x1)) -> x1 A(a(x1)) -> x1 b(B(x1)) -> x1 B(b(x1)) -> x1 c(C(x1)) -> x1 C(c(x1)) -> x1 Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: c(b(a(x1))) -> a(b(c(x1))) A(B(C(x1))) -> C(B(A(x1))) C(a(b(x1))) -> b(a(C(x1))) B(A(c(x1))) -> c(A(B(x1))) b(c(A(x1))) -> A(c(b(x1))) a(C(B(x1))) -> B(C(a(x1))) A(a(x1)) -> x1 a(A(x1)) -> x1 B(b(x1)) -> x1 b(B(x1)) -> x1 C(c(x1)) -> x1 c(C(x1)) -> x1 Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(A(x_1)) = 1 + x_1 POL(B(x_1)) = x_1 POL(C(x_1)) = x_1 POL(a(x_1)) = x_1 POL(b(x_1)) = x_1 POL(c(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: A(a(x1)) -> x1 a(A(x1)) -> x1 popout

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