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SRS Standard pair #487091480
details
property
value
status
complete
benchmark
z008.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n141.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.356 seconds
cpu usage
4.28543
user time
3.3384
system time
0.94703
max virtual memory
5916124.0
max residence set size
67516.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(s(x1)) -> s(a(x1)) b(a(b(s(x1)))) -> a(b(s(a(x1)))) b(a(b(b(x1)))) -> a(b(a(b(x1)))) a(b(a(a(x1)))) -> b(a(b(a(x1)))) Proof: String Reversal Processor: s(a(x1)) -> a(s(x1)) s(b(a(b(x1)))) -> a(s(b(a(x1)))) b(b(a(b(x1)))) -> b(a(b(a(x1)))) a(a(b(a(x1)))) -> a(b(a(b(x1)))) Matrix Interpretation Processor: dim=1 interpretation: [a](x0) = 2x0 + 1, [s](x0) = 3x0 + 1, [b](x0) = 2x0 + 1 orientation: s(a(x1)) = 6x1 + 4 >= 6x1 + 3 = a(s(x1)) s(b(a(b(x1)))) = 24x1 + 22 >= 24x1 + 21 = a(s(b(a(x1)))) b(b(a(b(x1)))) = 16x1 + 15 >= 16x1 + 15 = b(a(b(a(x1)))) a(a(b(a(x1)))) = 16x1 + 15 >= 16x1 + 15 = a(b(a(b(x1)))) problem: b(b(a(b(x1)))) -> b(a(b(a(x1)))) a(a(b(a(x1)))) -> a(b(a(b(x1)))) Bounds Processor: bound: 0 enrichment: match automaton: final states: {6,1} transitions: a0(7) -> 8* a0(4) -> 5* a0(9) -> 6* a0(2) -> 3* f30() -> 2* b0(3) -> 4* b0(2) -> 7* b0(8) -> 9* b0(5) -> 1* 6 -> 3* 1 -> 7* problem: Qed
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