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SRS Standard pair #487091498
details
property
value
status
complete
benchmark
z122.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n023.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.35895 seconds
cpu usage
4.19386
user time
3.14371
system time
1.05016
max virtual memory
5930528.0
max residence set size
67224.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(a(x1)) -> b(c(x1)) b(b(x1)) -> c(d(x1)) c(c(x1)) -> d(d(d(x1))) d(c(x1)) -> b(f(x1)) d(d(d(x1))) -> a(c(x1)) f(f(x1)) -> f(b(x1)) Proof: String Reversal Processor: a(a(x1)) -> c(b(x1)) b(b(x1)) -> d(c(x1)) c(c(x1)) -> d(d(d(x1))) c(d(x1)) -> f(b(x1)) d(d(d(x1))) -> c(a(x1)) f(f(x1)) -> b(f(x1)) Matrix Interpretation Processor: dim=1 interpretation: [f](x0) = x0 + 5, [c](x0) = x0 + 6, [d](x0) = x0 + 4, [a](x0) = x0 + 6, [b](x0) = x0 + 5 orientation: a(a(x1)) = x1 + 12 >= x1 + 11 = c(b(x1)) b(b(x1)) = x1 + 10 >= x1 + 10 = d(c(x1)) c(c(x1)) = x1 + 12 >= x1 + 12 = d(d(d(x1))) c(d(x1)) = x1 + 10 >= x1 + 10 = f(b(x1)) d(d(d(x1))) = x1 + 12 >= x1 + 12 = c(a(x1)) f(f(x1)) = x1 + 10 >= x1 + 10 = b(f(x1)) problem: b(b(x1)) -> d(c(x1)) c(c(x1)) -> d(d(d(x1))) c(d(x1)) -> f(b(x1)) d(d(d(x1))) -> c(a(x1)) f(f(x1)) -> b(f(x1)) String Reversal Processor: b(b(x1)) -> c(d(x1)) c(c(x1)) -> d(d(d(x1))) d(c(x1)) -> b(f(x1)) d(d(d(x1))) -> a(c(x1)) f(f(x1)) -> f(b(x1)) WPO Processor: algebra: Sum weight function: w0 = 0 w(c) = 3 w(f) = w(b) = 2 w(d) = 1 w(a) = 0 status function: st(f) = st(d) = st(b) = st(c) = st(a) = [0] precedence: f > d > b > c ~ a problem: Qed
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