details

property	value
status	complete
benchmark	z117.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n184.star.cs.uiowa.edu
space	Zantema_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	10.012 seconds
cpu usage	35.4901
user time	34.3281
system time	1.16206
max virtual memory	9.8594688E7
max residence set size	3891616.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 16 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 56 ms] (6) QDP (7) DependencyGraphProof [EQUIVALENT, 0 ms] (8) QDP (9) QDPOrderProof [EQUIVALENT, 37 ms] (10) QDP (11) QDPOrderProof [EQUIVALENT, 1220 ms] (12) QDP (13) DependencyGraphProof [EQUIVALENT, 0 ms] (14) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: d(a(x1)) -> b(d(x1)) b(x1) -> a(a(a(x1))) c(d(c(x1))) -> a(d(x1)) b(d(d(x1))) -> c(c(d(d(c(x1))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(d(x1)) -> d(b(x1)) b(x1) -> a(a(a(x1))) c(d(c(x1))) -> d(a(x1)) d(d(b(x1))) -> c(d(d(c(c(x1))))) Q is empty. ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: A(d(x1)) -> D(b(x1)) A(d(x1)) -> B(x1) B(x1) -> A(a(a(x1))) B(x1) -> A(a(x1)) B(x1) -> A(x1) C(d(c(x1))) -> D(a(x1)) C(d(c(x1))) -> A(x1) D(d(b(x1))) -> C(d(d(c(c(x1))))) D(d(b(x1))) -> D(d(c(c(x1)))) D(d(b(x1))) -> D(c(c(x1))) D(d(b(x1))) -> C(c(x1)) D(d(b(x1))) -> C(x1) The TRS R consists of the following rules: a(d(x1)) -> d(b(x1)) b(x1) -> a(a(a(x1))) c(d(c(x1))) -> d(a(x1)) d(d(b(x1))) -> c(d(d(c(c(x1))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. A(d(x1)) -> B(x1) C(d(c(x1))) -> A(x1) D(d(b(x1))) -> D(c(c(x1))) popout

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