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SRS Standard pair #487091616
details
property
value
status
complete
benchmark
z101.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n144.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
1.02859 seconds
cpu usage
0.810909
user time
0.523904
system time
0.287005
max virtual memory
452896.0
max residence set size
5884.0
stage attributes
key
value
starexec-result
YES
output
YES Problem 1: (VAR v_NonEmpty:S x1:S) (RULES a(a(x1:S)) -> b(b(b(x1:S))) b(b(b(b(b(x1:S))))) -> a(a(a(x1:S))) ) Problem 1: Dependency Pairs Processor: -> Pairs: A(a(x1:S)) -> B(b(b(x1:S))) A(a(x1:S)) -> B(b(x1:S)) A(a(x1:S)) -> B(x1:S) B(b(b(b(b(x1:S))))) -> A(a(a(x1:S))) B(b(b(b(b(x1:S))))) -> A(a(x1:S)) B(b(b(b(b(x1:S))))) -> A(x1:S) -> Rules: a(a(x1:S)) -> b(b(b(x1:S))) b(b(b(b(b(x1:S))))) -> a(a(a(x1:S))) Problem 1: SCC Processor: -> Pairs: A(a(x1:S)) -> B(b(b(x1:S))) A(a(x1:S)) -> B(b(x1:S)) A(a(x1:S)) -> B(x1:S) B(b(b(b(b(x1:S))))) -> A(a(a(x1:S))) B(b(b(b(b(x1:S))))) -> A(a(x1:S)) B(b(b(b(b(x1:S))))) -> A(x1:S) -> Rules: a(a(x1:S)) -> b(b(b(x1:S))) b(b(b(b(b(x1:S))))) -> a(a(a(x1:S))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: A(a(x1:S)) -> B(b(b(x1:S))) A(a(x1:S)) -> B(b(x1:S)) A(a(x1:S)) -> B(x1:S) B(b(b(b(b(x1:S))))) -> A(a(a(x1:S))) B(b(b(b(b(x1:S))))) -> A(a(x1:S)) B(b(b(b(b(x1:S))))) -> A(x1:S) ->->-> Rules: a(a(x1:S)) -> b(b(b(x1:S))) b(b(b(b(b(x1:S))))) -> a(a(a(x1:S))) Problem 1: Reduction Pair Processor: -> Pairs: A(a(x1:S)) -> B(b(b(x1:S))) A(a(x1:S)) -> B(b(x1:S)) A(a(x1:S)) -> B(x1:S) B(b(b(b(b(x1:S))))) -> A(a(a(x1:S))) B(b(b(b(b(x1:S))))) -> A(a(x1:S)) B(b(b(b(b(x1:S))))) -> A(x1:S) -> Rules: a(a(x1:S)) -> b(b(b(x1:S))) b(b(b(b(b(x1:S))))) -> a(a(a(x1:S))) -> Usable rules: a(a(x1:S)) -> b(b(b(x1:S))) b(b(b(b(b(x1:S))))) -> a(a(a(x1:S))) ->Interpretation type: Linear ->Coefficients: All rationals ->Dimension: 1 ->Bound: 4 ->Interpretation: [a](X) = 3.X + 1/2 [b](X) = 2.X + 1/4 [A](X) = 3.X + 2 [B](X) = 2.X + 4/3 Problem 1: SCC Processor: -> Pairs: A(a(x1:S)) -> B(b(x1:S)) A(a(x1:S)) -> B(x1:S) B(b(b(b(b(x1:S))))) -> A(a(a(x1:S))) B(b(b(b(b(x1:S))))) -> A(a(x1:S)) B(b(b(b(b(x1:S))))) -> A(x1:S) -> Rules: a(a(x1:S)) -> b(b(b(x1:S))) b(b(b(b(b(x1:S))))) -> a(a(a(x1:S))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: A(a(x1:S)) -> B(b(x1:S)) A(a(x1:S)) -> B(x1:S) B(b(b(b(b(x1:S))))) -> A(a(a(x1:S))) B(b(b(b(b(x1:S))))) -> A(a(x1:S))
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