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SRS Standard pair #487091654
details
property
value
status
complete
benchmark
z019.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n151.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.891231 seconds
cpu usage
2.49584
user time
1.82561
system time
0.670224
max virtual memory
5906840.0
max residence set size
65016.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(b(x1)) -> b(c(a(x1))) b(c(x1)) -> c(b(b(x1))) c(a(x1)) -> a(c(x1)) Proof: String Reversal Processor: b(a(x1)) -> a(c(b(x1))) c(b(x1)) -> b(b(c(x1))) a(c(x1)) -> c(a(x1)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [a](x0) = [1 0 1]x0 + [0] [1 0 1] [1], [1 0 1] [b](x0) = [0 0 1]x0 [0 1 1] , [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] orientation: [2 0 1] [1] [1 0 1] [0] b(a(x1)) = [1 0 1]x1 + [1] >= [1 0 1]x1 + [0] = a(c(b(x1))) [2 0 2] [1] [1 0 1] [1] [1 0 1] [1 0 0] c(b(x1)) = [0 0 0]x1 >= [0 0 0]x1 = b(b(c(x1))) [0 0 0] [0 0 0] [1 0 0] [0] [1 0 0] a(c(x1)) = [1 0 0]x1 + [0] >= [0 0 0]x1 = c(a(x1)) [1 0 0] [1] [0 0 0] problem: c(b(x1)) -> b(b(c(x1))) a(c(x1)) -> c(a(x1)) String Reversal Processor: b(c(x1)) -> c(b(b(x1))) c(a(x1)) -> a(c(x1)) KBO Processor: weight function: w0 = 1 w(c) = w(a) = 1 w(b) = 0 precedence: b > c > a problem: Qed
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