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SRS Standard pair #487091708
details
property
value
status
complete
benchmark
z116.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n147.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.679047 seconds
cpu usage
1.66235
user time
1.18262
system time
0.479731
max virtual memory
5324404.0
max residence set size
59768.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(a(a(x1))) -> b(b(x1)) b(b(b(x1))) -> c(d(x1)) c(x1) -> a(a(x1)) d(x1) -> c(x1) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1 2] [1] [b](x0) = [0 0]x0 + [1], [1 2] [2] [c](x0) = [0 0]x0 + [1], [1 2] [0] [a](x0) = [0 0]x0 + [1], [1 2] [2] [d](x0) = [0 0]x0 + [1] orientation: [1 2] [4] [1 2] [4] a(a(a(x1))) = [0 0]x1 + [1] >= [0 0]x1 + [1] = b(b(x1)) [1 2] [7] [1 2] [6] b(b(b(x1))) = [0 0]x1 + [1] >= [0 0]x1 + [1] = c(d(x1)) [1 2] [2] [1 2] [2] c(x1) = [0 0]x1 + [1] >= [0 0]x1 + [1] = a(a(x1)) [1 2] [2] [1 2] [2] d(x1) = [0 0]x1 + [1] >= [0 0]x1 + [1] = c(x1) problem: a(a(a(x1))) -> b(b(x1)) c(x1) -> a(a(x1)) d(x1) -> c(x1) Bounds Processor: bound: 1 enrichment: match automaton: final states: {6,4,1} transitions: b0(3) -> 1* b0(2) -> 3* c0(2) -> 6* a1(10) -> 11* a1(11) -> 12* f40() -> 2* a0(2) -> 5* a0(5) -> 4* 12 -> 6* 2 -> 10* 1 -> 11,5,12,4,6 problem: Qed
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