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SRS Standard pair #487091756
details
property
value
status
complete
benchmark
z009.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n150.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.904452 seconds
cpu usage
2.34652
user time
1.75944
system time
0.587075
max virtual memory
5909900.0
max residence set size
59848.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(x1) -> b(c(x1)) a(b(x1)) -> b(a(x1)) d(c(x1)) -> d(a(x1)) a(c(x1)) -> c(a(x1)) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1 0] [0] [c](x0) = [0 2]x0 + [1], [1 2] [2] [d](x0) = [0 0]x0 + [0], [1 0] [a](x0) = [0 2]x0, [1 0] [b](x0) = [0 0]x0 orientation: [1 0] [1 0] a(x1) = [0 2]x1 >= [0 0]x1 = b(c(x1)) [1 0] [1 0] a(b(x1)) = [0 0]x1 >= [0 0]x1 = b(a(x1)) [1 4] [4] [1 4] [2] d(c(x1)) = [0 0]x1 + [0] >= [0 0]x1 + [0] = d(a(x1)) [1 0] [0] [1 0] [0] a(c(x1)) = [0 4]x1 + [2] >= [0 4]x1 + [1] = c(a(x1)) problem: a(x1) -> b(c(x1)) a(b(x1)) -> b(a(x1)) a(c(x1)) -> c(a(x1)) Bounds Processor: bound: 1 enrichment: match automaton: final states: {6,4,1} transitions: b0(3) -> 1* b0(5) -> 4* a0(2) -> 5* c0(2) -> 3* c0(5) -> 6* f40() -> 2* b1(8) -> 9* c1(7) -> 8* 4 -> 5* 2 -> 7* 6 -> 5* 9 -> 5* problem: Qed
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