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SRS Standard pair #487091780
details
property
value
status
complete
benchmark
z018.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n151.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.20043 seconds
cpu usage
3.66618
user time
2.71012
system time
0.956063
max virtual memory
5921016.0
max residence set size
62984.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(b(x1)) -> b(c(a(x1))) b(c(x1)) -> c(b(b(x1))) b(a(x1)) -> a(c(b(x1))) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [0] [a](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [1 0 0] [0] [b](x0) = [0 1 0]x0 + [1] [0 0 0] [0], [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] orientation: [1 1 0] [1] [1 1 0] [0] a(b(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = b(c(a(x1))) [0 0 0] [0] [0 0 0] [0] [1 0 0] [0] [1 0 0] b(c(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 = c(b(b(x1))) [0 0 0] [0] [0 0 0] [1 1 0] [0] [1 0 0] [0] b(a(x1)) = [0 0 0]x1 + [2] >= [0 0 0]x1 + [1] = a(c(b(x1))) [0 0 0] [0] [0 0 0] [0] problem: b(c(x1)) -> c(b(b(x1))) b(a(x1)) -> a(c(b(x1))) String Reversal Processor: c(b(x1)) -> b(b(c(x1))) a(b(x1)) -> b(c(a(x1))) WPO Processor: algebra: Sum weight function: w0 = 0 w(c) = w(a) = w(b) = 0 status function: st(c) = st(a) = st(b) = [0] precedence: a > c > b problem: Qed
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