details

property	value
status	complete
benchmark	z023.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n147.star.cs.uiowa.edu
space	Zantema_04

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	1.21045 seconds
cpu usage	3.71803
user time	2.95036
system time	0.767666
max virtual memory	5906544.0
max residence set size	67428.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: a(a(b(x1))) -> b(a(b(x1))) b(a(x1)) -> a(b(b(x1))) b(c(a(x1))) -> c(c(a(a(b(x1))))) Proof: String Reversal Processor: b(a(a(x1))) -> b(a(b(x1))) a(b(x1)) -> b(b(a(x1))) a(c(b(x1))) -> b(a(a(c(c(x1))))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [a](x0) = [0 1 1]x0 [0 0 0] , [1 0 0] [0] [b](x0) = [0 0 0]x0 + [1] [0 0 1] [0], [1 0 0] [c](x0) = [0 0 0]x0 [0 1 0] orientation: [1 0 1] [0] [1 0 1] [0] b(a(a(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = b(a(b(x1))) [0 0 0] [0] [0 0 0] [0] [1 0 1] [0] [1 0 1] [0] a(b(x1)) = [0 0 1]x1 + [1] >= [0 0 0]x1 + [1] = b(b(a(x1))) [0 0 0] [0] [0 0 0] [0] [1 0 0] [1] [1 0 0] [0] a(c(b(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = b(a(a(c(c(x1))))) [0 0 0] [0] [0 0 0] [0] problem: b(a(a(x1))) -> b(a(b(x1))) a(b(x1)) -> b(b(a(x1))) String Reversal Processor: a(a(b(x1))) -> b(a(b(x1))) b(a(x1)) -> a(b(b(x1))) KBO Processor: weight function: w0 = 1 w(a) = 1 w(b) = 0 precedence: b > a problem: Qed popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to SRS Standard