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SRS Standard pair #487091930
details
property
value
status
complete
benchmark
dup12.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n141.star.cs.uiowa.edu
space
Trafo_06
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
4.88096 seconds
cpu usage
18.0085
user time
15.883
system time
2.12547
max virtual memory
6078472.0
max residence set size
73704.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: b(b(d(d(b(b(x1)))))) -> c(c(d(d(b(b(x1)))))) b(b(a(a(c(c(x1)))))) -> b(b(c(c(x1)))) a(a(d(d(x1)))) -> d(d(c(c(x1)))) b(b(b(b(b(b(x1)))))) -> a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) -> b(b(d(d(x1)))) d(d(c(c(x1)))) -> d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) -> b(b(b(b(x1)))) Proof: Matrix Interpretation Processor: dim=1 interpretation: [d](x0) = x0, [a](x0) = x0 + 1, [b](x0) = x0 + 1, [c](x0) = x0 + 1 orientation: b(b(d(d(b(b(x1)))))) = x1 + 4 >= x1 + 4 = c(c(d(d(b(b(x1)))))) b(b(a(a(c(c(x1)))))) = x1 + 6 >= x1 + 4 = b(b(c(c(x1)))) a(a(d(d(x1)))) = x1 + 2 >= x1 + 2 = d(d(c(c(x1)))) b(b(b(b(b(b(x1)))))) = x1 + 6 >= x1 + 6 = a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) = x1 + 2 >= x1 + 2 = b(b(d(d(x1)))) d(d(c(c(x1)))) = x1 + 2 >= x1 + 2 = d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) = x1 + 4 >= x1 + 4 = b(b(b(b(x1)))) problem: b(b(d(d(b(b(x1)))))) -> c(c(d(d(b(b(x1)))))) a(a(d(d(x1)))) -> d(d(c(c(x1)))) b(b(b(b(b(b(x1)))))) -> a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) -> b(b(d(d(x1)))) d(d(c(c(x1)))) -> d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) -> b(b(b(b(x1)))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [d](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [1 1 0] [a](x0) = [0 0 1]x0 [0 1 0] , [1 0 0] [b](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] orientation: [1 0 0] [1 0 0] b(b(d(d(b(b(x1)))))) = [0 0 0]x1 >= [0 0 0]x1 = c(c(d(d(b(b(x1)))))) [0 0 0] [0 0 0] [1 0 0] [1] [1 0 0] [0] a(a(d(d(x1)))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = d(d(c(c(x1)))) [0 0 0] [0] [0 0 0] [0] [1 0 0] [1 0 0] b(b(b(b(b(b(x1)))))) = [0 0 0]x1 >= [0 0 0]x1 = a(a(b(b(c(c(x1)))))) [0 0 0] [0 0 0] [1 0 0] [0] [1 0 0] d(d(c(c(x1)))) = [0 0 0]x1 + [1] >= [0 0 0]x1 = b(b(d(d(x1)))) [0 0 0] [0] [0 0 0] [1 0 0] [0] [1 0 0] [0] d(d(c(c(x1)))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = d(d(b(b(d(d(x1)))))) [0 0 0] [0] [0 0 0] [0] [1 0 0] [0] [1 0 0] d(d(a(a(c(c(x1)))))) = [0 0 0]x1 + [1] >= [0 0 0]x1 = b(b(b(b(x1)))) [0 0 0] [0] [0 0 0] problem: b(b(d(d(b(b(x1)))))) -> c(c(d(d(b(b(x1)))))) b(b(b(b(b(b(x1)))))) -> a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) -> b(b(d(d(x1)))) d(d(c(c(x1)))) -> d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) -> b(b(b(b(x1)))) String Reversal Processor: b(b(d(d(b(b(x1)))))) -> b(b(d(d(c(c(x1)))))) b(b(b(b(b(b(x1)))))) -> c(c(b(b(a(a(x1)))))) c(c(d(d(x1)))) -> d(d(b(b(x1)))) c(c(d(d(x1)))) -> d(d(b(b(d(d(x1)))))) c(c(a(a(d(d(x1)))))) -> b(b(b(b(x1)))) Bounds Processor: bound: 1 enrichment: match
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