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SRS Standard pair #487091936
details
property
value
status
complete
benchmark
dup15.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n053.star.cs.uiowa.edu
space
Trafo_06
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.30962 seconds
cpu usage
4.07814
user time
3.38474
system time
0.6934
max virtual memory
5993588.0
max residence set size
68884.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(a(d(d(x1)))) -> d(d(b(b(x1)))) a(a(x1)) -> b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) c(c(x1)) -> d(d(x1)) Proof: Matrix Interpretation Processor: dim=1 interpretation: [a](x0) = x0 + 8, [c](x0) = 2x0 + 1, [d](x0) = 2x0, [b](x0) = x0 + 2 orientation: a(a(d(d(x1)))) = 4x1 + 16 >= 4x1 + 16 = d(d(b(b(x1)))) a(a(x1)) = x1 + 16 >= x1 + 12 = b(b(b(b(b(b(x1)))))) b(b(d(d(b(b(x1)))))) = 4x1 + 20 >= 4x1 + 19 = a(a(c(c(x1)))) c(c(x1)) = 4x1 + 3 >= 4x1 = d(d(x1)) problem: a(a(d(d(x1)))) -> d(d(b(b(x1)))) KBO Processor: weight function: w0 = 1 w(a) = w(d) = 1 w(b) = 0 precedence: b > d > a problem: Qed
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