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SRS Standard pair #487092008
details
property
value
status
complete
benchmark
dup17.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n150.star.cs.uiowa.edu
space
Trafo_06
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
2.04741 seconds
cpu usage
6.71727
user time
5.76163
system time
0.955641
max virtual memory
6045788.0
max residence set size
71716.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(a(a(a(x1)))) -> b(b(x1)) b(b(a(a(x1)))) -> a(a(b(b(x1)))) b(b(b(b(c(c(x1)))))) -> c(c(a(a(x1)))) b(b(b(b(x1)))) -> a(a(a(a(a(a(x1)))))) c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) Proof: Matrix Interpretation Processor: dim=1 interpretation: [b](x0) = x0 + 2, [a](x0) = x0 + 1, [c](x0) = 2x0 orientation: a(a(a(a(x1)))) = x1 + 4 >= x1 + 4 = b(b(x1)) b(b(a(a(x1)))) = x1 + 6 >= x1 + 6 = a(a(b(b(x1)))) b(b(b(b(c(c(x1)))))) = 4x1 + 8 >= 4x1 + 8 = c(c(a(a(x1)))) b(b(b(b(x1)))) = x1 + 8 >= x1 + 6 = a(a(a(a(a(a(x1)))))) c(c(a(a(x1)))) = 4x1 + 8 >= 4x1 + 6 = b(b(a(a(c(c(x1)))))) problem: a(a(a(a(x1)))) -> b(b(x1)) b(b(a(a(x1)))) -> a(a(b(b(x1)))) b(b(b(b(c(c(x1)))))) -> c(c(a(a(x1)))) KBO Processor: weight function: w0 = 1 w(b) = w(a) = 1 w(c) = 0 precedence: c > b > a problem: Qed
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