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SRS Standard pair #487092026
details
property
value
status
complete
benchmark
dup08.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n022.star.cs.uiowa.edu
space
Trafo_06
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
7.46037 seconds
cpu usage
28.2184
user time
26.9526
system time
1.26582
max virtual memory
6056324.0
max residence set size
115704.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: a(a(a(a(b(b(x1)))))) -> b(b(a(a(b(b(x1)))))) b(b(a(a(x1)))) -> a(a(b(b(b(b(x1)))))) b(b(c(c(a(a(x1)))))) -> c(c(c(c(a(a(a(a(b(b(x1)))))))))) Proof: Matrix Interpretation Processor: dim=4 interpretation: [1 0 0 0] [0] [0 0 0 0] [0] [a](x0) = [0 0 0 1]x0 + [1] [0 1 0 1] [0], [1 1 0 0] [0] [0 0 0 1] [0] [b](x0) = [0 0 0 0]x0 + [1] [0 0 0 0] [0], [1 0 0 0] [0 0 1 0] [c](x0) = [0 0 0 0]x0 [0 1 1 0] orientation: [1 1 0 1] [0] [1 1 0 1] [0] [0 0 0 0] [0] [0 0 0 0] [0] a(a(a(a(b(b(x1)))))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = b(b(a(a(b(b(x1)))))) [0 0 0 0] [0] [0 0 0 0] [0] [1 1 0 1] [0] [1 1 0 1] [0] [0 0 0 0] [0] [0 0 0 0] [0] b(b(a(a(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = a(a(b(b(b(b(x1)))))) [0 0 0 0] [0] [0 0 0 0] [0] [1 1 0 1] [1] [1 1 0 1] [0 0 0 0] [0] [0 0 0 0] b(b(c(c(a(a(x1)))))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 = c(c(c(c(a(a(a(a(b(b(x1)))))))))) [0 0 0 0] [0] [0 0 0 0] problem: a(a(a(a(b(b(x1)))))) -> b(b(a(a(b(b(x1)))))) b(b(a(a(x1)))) -> a(a(b(b(b(b(x1)))))) KBO Processor: weight function: w0 = 1 w(a) = 1 w(b) = 0 precedence: b > a problem: Qed
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