details

property	value
status	complete
benchmark	hom03.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n022.star.cs.uiowa.edu
space	Trafo_06

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.63802 seconds
cpu usage	7.17024
user time	6.84195
system time	0.328283
max virtual memory	1.867802E7
max residence set size	286372.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(a(b(c(a(a(a(x1))))))))) -> a(a(a(a(b(c(a(b(c(a(b(c(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(c(b(a(c(b(a(x1))))))))) -> c(b(a(c(b(a(c(b(a(a(a(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(c(b(a(c(b(a(x1))))))))) -> c(b(a(c(b(a(c(b(a(a(a(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(c(b(a(c(b(x)))))))) -> c(b(a(c(b(a(c(b(a(a(a(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(c(b(a(c(b(x)))))))) -> c(b(a(c(b(a(c(b(a(a(a(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(c(b(a(c(b(x)))))))) -> c(b(a(c(b(a(c(b(a(a(a(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 474, 475, 476, 477, 478, 479, 480, 481, 482, 483, 484, 485, 486, 487, 488, 489, 490, 491, 492, 493, 494, 495 Node 474 is start node and node 475 is final node. Those nodes are connected through the following edges: * 474 to 476 labelled c_1(0)* 475 to 475 labelled #_1(0)* 476 to 477 labelled b_1(0)* 477 to 478 labelled a_1(0)* 478 to 479 labelled c_1(0)* 479 to 480 labelled b_1(0)* 480 to 481 labelled a_1(0)* 481 to 482 labelled c_1(0)* 482 to 483 labelled b_1(0)* 483 to 484 labelled a_1(0)* 483 to 486 labelled c_1(1)* 484 to 485 labelled a_1(0)* 484 to 486 labelled c_1(1)* 485 to 475 labelled a_1(0)* 485 to 486 labelled c_1(1)* 486 to 487 labelled b_1(1)* 487 to 488 labelled a_1(1)* 488 to 489 labelled c_1(1)* 489 to 490 labelled b_1(1)* 490 to 491 labelled a_1(1)* 491 to 492 labelled c_1(1)* 492 to 493 labelled b_1(1)* 493 to 494 labelled a_1(1)* 493 to 486 labelled c_1(1)* 494 to 495 labelled a_1(1)* 494 to 486 labelled c_1(1)* 495 to 475 labelled a_1(1)* 495 to 486 labelled c_1(1) ---------------------------------------- (6) YES popout

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