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SRS Standard pair #487092196
details
property
value
status
complete
benchmark
size-11-alpha-3-num-15.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n142.star.cs.uiowa.edu
space
Waldmann_07_size11
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
5.08246 seconds
cpu usage
17.2567
user time
16.5706
system time
0.686097
max virtual memory
3.964002E7
max residence set size
2070360.0
stage attributes
key
value
starexec-result
NO
output
NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 867 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(b(x1))) -> b(c(b(a(a(a(x1)))))) a(c(x1)) -> x1 Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a a b a b c b b c b -> b c b b c b b c b a b c b a a b a b c b b c b a a a" a a b a b c b b c b -> b c b b c b b c b a b c b a a b a b c b b c b a a a by OverlapClosure OC 2"a a b a b c b b c -> b c b b c b b c b a b c b a a b a b c b a a by OverlapClosure OC 2"a a b a b c b -> b c b b c b b c b a b c b a a b a a a by OverlapClosure OC 3"a a b a b c b -> b c b b c b b c b a a a b c b a a a by OverlapClosure OC 2"a a b a b c -> b c b b c b b c b a a a a a by OverlapClosure OC 3"a a b a b c -> b c b b c b a a b a a by OverlapClosure OC 3"a a b a b c -> b c b a a b c b a a by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a a b c -> b c b a a by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a c -> by original rule (OC 1)""""a a b c -> b c b a a by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a c -> by original rule (OC 1)""""a a b -> b c b a a a by original rule (OC 1)"""a a b -> b c b a a a by original rule (OC 1)"""a a b c -> b c b a a by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a c -> by original rule (OC 1)""""a a b c -> b c b a a by OverlapClosure OC 2"a a b -> b c b a a a by original rule (OC 1)""a c -> by original rule (OC 1)""""a a b -> b c b a a a by original rule (OC 1)" ---------------------------------------- (2) NO
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