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TRS Contextsensitive pair #487092474
details
property
value
status
complete
benchmark
ex5.6.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n147.star.cs.uiowa.edu
space
Transformed_outermost_08
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.035861 seconds
cpu usage
0.031531
user time
0.012267
system time
0.019264
max virtual memory
113188.0
max residence set size
4440.0
stage attributes
key
value
starexec-result
YES
output
YES Problem 1: (VAR x y) (STRATEGY CONTEXTSENSITIVE (f_1) (g_1) (a_0) (i_0 1) ) (RULES f_1(x,i_0(g_1(x))) -> a_0 f_1(x,i_0(x)) -> f_1(x,x) f_1(x,x) -> f_1(i_0(x),g_1(g_1(x))) f_1(x,y) -> x g_1(x) -> i_0(x) ) Problem 1: Dependency Pairs Processor: -> Pairs: F_1(x,i_0(x)) -> F_1(x,x) F_1(x,x) -> F_1(i_0(x),g_1(g_1(x))) F_1(x,y) -> x G_1(x) -> x -> Rules: f_1(x,i_0(g_1(x))) -> a_0 f_1(x,i_0(x)) -> f_1(x,x) f_1(x,x) -> f_1(i_0(x),g_1(g_1(x))) f_1(x,y) -> x g_1(x) -> i_0(x) -> Unhiding Rules: g_1(g_1(x)) -> G_1(g_1(x)) i_0(x2) -> x2 Problem 1: SCC Processor: -> Pairs: F_1(x,i_0(x)) -> F_1(x,x) F_1(x,x) -> F_1(i_0(x),g_1(g_1(x))) F_1(x,y) -> x G_1(x) -> x -> Rules: f_1(x,i_0(g_1(x))) -> a_0 f_1(x,i_0(x)) -> f_1(x,x) f_1(x,x) -> f_1(i_0(x),g_1(g_1(x))) f_1(x,y) -> x g_1(x) -> i_0(x) -> Unhiding rules: g_1(g_1(x)) -> G_1(g_1(x)) i_0(x2) -> x2 ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: G_1(x) -> x ->->-> Rules: f_1(x,i_0(g_1(x))) -> a_0 f_1(x,i_0(x)) -> f_1(x,x) f_1(x,x) -> f_1(i_0(x),g_1(g_1(x))) f_1(x,y) -> x g_1(x) -> i_0(x) ->->-> Unhiding rules: g_1(g_1(x)) -> G_1(g_1(x)) i_0(x2) -> x2 Problem 1: Reduction Pairs Processor: -> Pairs: G_1(x) -> x -> Rules: f_1(x,i_0(g_1(x))) -> a_0 f_1(x,i_0(x)) -> f_1(x,x) f_1(x,x) -> f_1(i_0(x),g_1(g_1(x))) f_1(x,y) -> x g_1(x) -> i_0(x) -> Unhiding rules: g_1(g_1(x)) -> G_1(g_1(x)) i_0(x2) -> x2 -> Usable rules: g_1(x) -> i_0(x) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [g_1](X) = 2.X + 2 [i_0](X) = 2.X [G_1](X) = 2.X + 2 Problem 1:
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