details

property	value
status	complete
benchmark	ExIntrod_GM01.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	CSR_04

run statistics

property	value
solver	muterm 5.18
configuration	default
runtime (wallclock)	0.0209859 seconds
cpu usage	0.016297
user time	0.007591
system time	0.008706
max virtual memory	0.0
max residence set size	4968.0

stage attributes

key	value
starexec-result	YES

output

YES Problem 1: (VAR L X) (STRATEGY CONTEXTSENSITIVE (adx 1) (head 1) (incr 1) (nats) (tail 1) (zeros) (0) (cons 1) (nil) (s 1) ) (RULES adx(cons(X,L)) -> incr(cons(X,adx(L))) adx(nil) -> nil head(cons(X,L)) -> X incr(cons(X,L)) -> cons(s(X),incr(L)) incr(nil) -> nil nats -> adx(zeros) tail(cons(X,L)) -> L zeros -> cons(0,zeros) ) Problem 1: Innermost Equivalent Processor: -> Rules: adx(cons(X,L)) -> incr(cons(X,adx(L))) adx(nil) -> nil head(cons(X,L)) -> X incr(cons(X,L)) -> cons(s(X),incr(L)) incr(nil) -> nil nats -> adx(zeros) tail(cons(X,L)) -> L zeros -> cons(0,zeros) -> The context-sensitive term rewriting system is an orthogonal system. Therefore, innermost cs-termination implies cs-termination. Problem 1: Dependency Pairs Processor: -> Pairs: ADX(cons(X,L)) -> INCR(cons(X,adx(L))) NATS -> ADX(zeros) NATS -> ZEROS TAIL(cons(X,L)) -> L -> Rules: adx(cons(X,L)) -> incr(cons(X,adx(L))) adx(nil) -> nil head(cons(X,L)) -> X incr(cons(X,L)) -> cons(s(X),incr(L)) incr(nil) -> nil nats -> adx(zeros) tail(cons(X,L)) -> L zeros -> cons(0,zeros) -> Unhiding Rules: adx(L) -> ADX(L) adx(x2) -> x2 incr(L) -> INCR(L) incr(x2) -> x2 zeros -> ZEROS Problem 1: SCC Processor: -> Pairs: ADX(cons(X,L)) -> INCR(cons(X,adx(L))) NATS -> ADX(zeros) NATS -> ZEROS TAIL(cons(X,L)) -> L -> Rules: adx(cons(X,L)) -> incr(cons(X,adx(L))) adx(nil) -> nil head(cons(X,L)) -> X incr(cons(X,L)) -> cons(s(X),incr(L)) incr(nil) -> nil nats -> adx(zeros) tail(cons(X,L)) -> L zeros -> cons(0,zeros) -> Unhiding rules: adx(L) -> ADX(L) adx(x2) -> x2 incr(L) -> INCR(L) incr(x2) -> x2 zeros -> ZEROS ->Strongly Connected Components: There is no strongly connected component The problem is finite. popout

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