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TRS Equational pair #487092681
details
property
value
status
complete
benchmark
AC01.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n142.star.cs.uiowa.edu
space
AProVE_AC_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.199498 seconds
cpu usage
0.176478
user time
0.083159
system time
0.093319
max virtual memory
113188.0
max residence set size
4984.0
stage attributes
key
value
starexec-result
YES
output
YES Problem 1: (VAR x y) (THEORY (AC plus)) (RULES plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) ) Problem 1: Reduction Order Processor: -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [plus](X1,X2) = X1 + X2 + 2 [0] = 2 [s](X) = X + 2 Problem 1: Dependency Pairs Processor: -> FAxioms: PLUS(plus(x2,x3),x4) = PLUS(x2,plus(x3,x4)) PLUS(x2,x3) = PLUS(x3,x2) -> Pairs: PLUS(plus(x,s(y)),x2) -> PLUS(s(plus(x,y)),x2) PLUS(plus(x,s(y)),x2) -> PLUS(x,y) PLUS(x,s(y)) -> PLUS(x,y) -> EAxioms: plus(plus(x2,x3),x4) = plus(x2,plus(x3,x4)) plus(x2,x3) = plus(x3,x2) -> Rules: plus(x,s(y)) -> s(plus(x,y)) -> SRules: PLUS(plus(x2,x3),x4) -> PLUS(x2,x3) PLUS(x2,plus(x3,x4)) -> PLUS(x3,x4) Problem 1: SCC Processor: -> FAxioms: PLUS(plus(x2,x3),x4) = PLUS(x2,plus(x3,x4)) PLUS(x2,x3) = PLUS(x3,x2) -> Pairs: PLUS(plus(x,s(y)),x2) -> PLUS(s(plus(x,y)),x2) PLUS(plus(x,s(y)),x2) -> PLUS(x,y) PLUS(x,s(y)) -> PLUS(x,y) -> EAxioms: plus(plus(x2,x3),x4) = plus(x2,plus(x3,x4)) plus(x2,x3) = plus(x3,x2) -> Rules: plus(x,s(y)) -> s(plus(x,y)) -> SRules: PLUS(plus(x2,x3),x4) -> PLUS(x2,x3) PLUS(x2,plus(x3,x4)) -> PLUS(x3,x4) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: PLUS(plus(x,s(y)),x2) -> PLUS(s(plus(x,y)),x2) PLUS(plus(x,s(y)),x2) -> PLUS(x,y) PLUS(x,s(y)) -> PLUS(x,y) -> FAxioms: plus(plus(x2,x3),x4) -> plus(x2,plus(x3,x4)) plus(x2,x3) -> plus(x3,x2) PLUS(plus(x2,x3),x4) -> PLUS(x2,plus(x3,x4)) PLUS(x2,x3) -> PLUS(x3,x2) -> EAxioms: plus(plus(x2,x3),x4) = plus(x2,plus(x3,x4)) plus(x2,x3) = plus(x3,x2) ->->-> Rules: plus(x,s(y)) -> s(plus(x,y)) -> SRules: PLUS(plus(x2,x3),x4) -> PLUS(x2,x3) PLUS(x2,plus(x3,x4)) -> PLUS(x3,x4) Problem 1: Reduction Pairs Processor: -> FAxioms: PLUS(plus(x2,x3),x4) = PLUS(x2,plus(x3,x4)) PLUS(x2,x3) = PLUS(x3,x2) -> Pairs: PLUS(plus(x,s(y)),x2) -> PLUS(s(plus(x,y)),x2) PLUS(plus(x,s(y)),x2) -> PLUS(x,y) PLUS(x,s(y)) -> PLUS(x,y) -> EAxioms:
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