details

property	value
status	complete
benchmark	Ex24_GM04_GM.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	Transformed_CSR_innermost_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.63565 seconds
cpu usage	3.59687
user time	3.43819
system time	0.158681
max virtual memory	1.8343148E7
max residence set size	233784.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) UsableRulesProof [EQUIVALENT, 0 ms] (6) QDP (7) QReductionProof [EQUIVALENT, 0 ms] (8) QDP (9) QDPSizeChangeProof [EQUIVALENT, 0 ms] (10) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a__f(X, g(X), Y) -> a__f(Y, Y, Y) a__g(b) -> c a__b -> c mark(f(X1, X2, X3)) -> a__f(X1, X2, X3) mark(g(X)) -> a__g(mark(X)) mark(b) -> a__b mark(c) -> c a__f(X1, X2, X3) -> f(X1, X2, X3) a__g(X) -> g(X) a__b -> b The set Q consists of the following terms: a__b mark(f(x0, x1, x2)) mark(g(x0)) mark(b) mark(c) a__f(x0, x1, x2) a__g(x0) ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A__F(X, g(X), Y) -> A__F(Y, Y, Y) MARK(f(X1, X2, X3)) -> A__F(X1, X2, X3) MARK(g(X)) -> A__G(mark(X)) MARK(g(X)) -> MARK(X) MARK(b) -> A__B The TRS R consists of the following rules: a__f(X, g(X), Y) -> a__f(Y, Y, Y) a__g(b) -> c a__b -> c mark(f(X1, X2, X3)) -> a__f(X1, X2, X3) mark(g(X)) -> a__g(mark(X)) mark(b) -> a__b mark(c) -> c a__f(X1, X2, X3) -> f(X1, X2, X3) a__g(X) -> g(X) a__b -> b The set Q consists of the following terms: a__b mark(f(x0, x1, x2)) mark(g(x0)) mark(b) mark(c) a__f(x0, x1, x2) a__g(x0) We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 4 less nodes. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Innermost