TRS Innermost pair #487093267

details

property	value
status	complete
benchmark	Ex7_BLR02_C.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	Transformed_CSR_innermost_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.00498 seconds
cpu usage	4.09524
user time	3.92082
system time	0.17442
max virtual memory	1.8343376E7
max residence set size	243144.0

stage attributes

key	value
starexec-result	YES

output

YES
proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be proven:

(0) QTRS
(1) QTRSToCSRProof [SOUND, 0 ms]
(2) CSR
(3) CSRInnermostProof [EQUIVALENT, 0 ms]
(4) CSR
(5) CSDependencyPairsProof [EQUIVALENT, 17 ms]
(6) QCSDP
(7) QCSDependencyGraphProof [EQUIVALENT, 0 ms]
(8) AND
    (9) QCSDP
        (10) QCSDPSubtermProof [EQUIVALENT, 0 ms]
        (11) QCSDP
        (12) PIsEmptyProof [EQUIVALENT, 0 ms]
        (13) YES
    (14) QCSDP
        (15) QCSDPSubtermProof [EQUIVALENT, 0 ms]
        (16) QCSDP
        (17) PIsEmptyProof [EQUIVALENT, 0 ms]
        (18) YES


----------------------------------------

(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   active(from(X)) -> mark(cons(X, from(s(X))))
   active(head(cons(X, XS))) -> mark(X)
   active(2nd(cons(X, XS))) -> mark(head(XS))
   active(take(0, XS)) -> mark(nil)
   active(take(s(N), cons(X, XS))) -> mark(cons(X, take(N, XS)))
   active(sel(0, cons(X, XS))) -> mark(X)
   active(sel(s(N), cons(X, XS))) -> mark(sel(N, XS))
   active(from(X)) -> from(active(X))
   active(cons(X1, X2)) -> cons(active(X1), X2)
   active(s(X)) -> s(active(X))
   active(head(X)) -> head(active(X))
   active(2nd(X)) -> 2nd(active(X))
   active(take(X1, X2)) -> take(active(X1), X2)
   active(take(X1, X2)) -> take(X1, active(X2))
   active(sel(X1, X2)) -> sel(active(X1), X2)
   active(sel(X1, X2)) -> sel(X1, active(X2))
   from(mark(X)) -> mark(from(X))
   cons(mark(X1), X2) -> mark(cons(X1, X2))
   s(mark(X)) -> mark(s(X))
   head(mark(X)) -> mark(head(X))
   2nd(mark(X)) -> mark(2nd(X))
   take(mark(X1), X2) -> mark(take(X1, X2))
   take(X1, mark(X2)) -> mark(take(X1, X2))
   sel(mark(X1), X2) -> mark(sel(X1, X2))
   sel(X1, mark(X2)) -> mark(sel(X1, X2))
   proper(from(X)) -> from(proper(X))
   proper(cons(X1, X2)) -> cons(proper(X1), proper(X2))
   proper(s(X)) -> s(proper(X))
   proper(head(X)) -> head(proper(X))
   proper(2nd(X)) -> 2nd(proper(X))
   proper(take(X1, X2)) -> take(proper(X1), proper(X2))
   proper(0) -> ok(0)
   proper(nil) -> ok(nil)
   proper(sel(X1, X2)) -> sel(proper(X1), proper(X2))
   from(ok(X)) -> ok(from(X))
   cons(ok(X1), ok(X2)) -> ok(cons(X1, X2))
   s(ok(X)) -> ok(s(X))
   head(ok(X)) -> ok(head(X))
   2nd(ok(X)) -> ok(2nd(X))
   take(ok(X1), ok(X2)) -> ok(take(X1, X2))
   sel(ok(X1), ok(X2)) -> ok(sel(X1, X2))
   top(mark(X)) -> top(proper(X))
   top(ok(X)) -> top(active(X))

The set Q consists of the following terms:

   active(from(x0))
   active(cons(x0, x1))
   active(s(x0))
   active(head(x0))
   active(2nd(x0))
   active(take(x0, x1))
   active(sel(x0, x1))
   from(mark(x0))
   cons(mark(x0), x1)
   s(mark(x0))
   head(mark(x0))
   2nd(mark(x0))
   take(mark(x0), x1)
   take(x0, mark(x1))
   sel(mark(x0), x1)
   sel(x0, mark(x1))
   proper(from(x0))
   proper(cons(x0, x1))
   proper(s(x0))

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