details

property	value
status	complete
benchmark	Ex24_Luc06_GM.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n147.star.cs.uiowa.edu
space	Transformed_CSR_innermost_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.76145 seconds
cpu usage	3.94939
user time	3.76117
system time	0.188214
max virtual memory	1.8408912E7
max residence set size	256216.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 47 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 0 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 5 ms] (6) QTRS (7) DependencyPairsProof [EQUIVALENT, 0 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a__f(b, X, c) -> a__f(X, a__c, X) a__c -> b mark(f(X1, X2, X3)) -> a__f(X1, mark(X2), X3) mark(c) -> a__c mark(b) -> b a__f(X1, X2, X3) -> f(X1, X2, X3) a__c -> c The set Q consists of the following terms: a__c mark(f(x0, x1, x2)) mark(c) mark(b) a__f(x0, x1, x2) ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(a__c) = 0 POL(a__f(x_1, x_2, x_3)) = 2 + x_1 + 2*x_2 + x_3 POL(b) = 0 POL(c) = 0 POL(f(x_1, x_2, x_3)) = 2 + x_1 + 2*x_2 + x_3 POL(mark(x_1)) = 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: mark(f(X1, X2, X3)) -> a__f(X1, mark(X2), X3) ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a__f(b, X, c) -> a__f(X, a__c, X) a__c -> b mark(c) -> a__c mark(b) -> b a__f(X1, X2, X3) -> f(X1, X2, X3) a__c -> c The set Q consists of the following terms: a__c mark(f(x0, x1, x2)) mark(c) mark(b) a__f(x0, x1, x2) ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(a__c) = 0 POL(a__f(x_1, x_2, x_3)) = 1 + x_1 + 2*x_2 + x_3 POL(b) = 0 POL(c) = 0 POL(f(x_1, x_2, x_3)) = x_1 + 2*x_2 + x_3 POL(mark(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Innermost