details

property	value
status	complete
benchmark	h00.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n151.star.cs.uiowa.edu
space	Hamana_Kikuchi_18

run statistics

property	value
solver	Wanda 2.2a
configuration	default
runtime (wallclock)	0.606572 seconds
cpu usage	0.583091
user time	0.514502
system time	0.068589
max virtual memory	128312.0
max residence set size	13920.0

stage attributes

key	value
starexec-result	YES

output

YES We consider the system theBenchmark. Alphabet: 0 : [] --> c add : [] --> a -> c -> c cons : [] --> a -> b -> b fold : [] --> (a -> c -> c) -> c -> b -> c mul : [] --> a -> c -> c nil : [] --> b plus : [] --> c -> c -> c prod : [] --> b -> c s : [] --> c -> c sum : [] --> b -> c times : [] --> c -> c -> c Rules: fold (/\x./\y.f x y) z nil => z fold (/\x./\y.f x y) z (cons u v) => f u (fold (/\w./\x'.f w x') z v) plus 0 x => x plus (s x) y => s (plus x y) times 0 x => 0 times (s x) y => plus (times x y) y sum x => fold (/\y./\z.add y z) 0 x prod x => fold (/\y./\z.mul y z) (s 0) x Using the transformations described in [Kop11], this system can be brought in a form without leading free variables in the left-hand side, and where the left-hand side of a variable is always a functional term or application headed by a functional term. We now transform the resulting AFS into an AFSM by replacing all free variables by meta-variables (with arity 0). This leads to the following AFSM: Alphabet: 0 : [] --> c add : [] --> a -> c -> c cons : [a * b] --> b fold : [a -> c -> c * c * b] --> c mul : [] --> a -> c -> c nil : [] --> b plus : [c * c] --> c prod : [b] --> c s : [c] --> c sum : [b] --> c times : [c * c] --> c ~AP1 : [a -> c -> c * a] --> c -> c Rules: fold(/\x./\y.~AP1(F, x) y, X, nil) => X fold(/\x./\y.~AP1(F, x) y, X, cons(Y, Z)) => ~AP1(F, Y) fold(/\z./\u.~AP1(F, z) u, X, Z) plus(0, X) => X plus(s(X), Y) => s(plus(X, Y)) times(0, X) => 0 times(s(X), Y) => plus(times(X, Y), Y) sum(X) => fold(/\x./\y.~AP1(add, x) y, 0, X) prod(X) => fold(/\x./\y.~AP1(mul, x) y, s(0), X) ~AP1(F, X) => F X Symbol ~AP1 is an encoding for application that is only used in innocuous ways. We can simplify the program (without losing non-termination) by removing it. This gives: Alphabet: 0 : [] --> c add : [a * c] --> c cons : [a * b] --> b fold : [a -> c -> c * c * b] --> c mul : [a * c] --> c nil : [] --> b plus : [c * c] --> c prod : [b] --> c s : [c] --> c sum : [b] --> c times : [c * c] --> c Rules: fold(/\x./\y.X(x, y), Y, nil) => Y fold(/\x./\y.X(x, y), Y, cons(Z, U)) => X(Z, fold(/\z./\u.X(z, u), Y, U)) plus(0, X) => X plus(s(X), Y) => s(plus(X, Y)) times(0, X) => 0 times(s(X), Y) => plus(times(X, Y), Y) sum(X) => fold(/\x./\y.add(x, y), 0, X) prod(X) => fold(/\x./\y.mul(x, y), s(0), X) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): fold(/\x./\y.X(x, y), Y, nil) >? Y fold(/\x./\y.X(x, y), Y, cons(Z, U)) >? X(Z, fold(/\z./\u.X(z, u), Y, U)) plus(0, X) >? X plus(s(X), Y) >? s(plus(X, Y)) times(0, X) >? 0 times(s(X), Y) >? plus(times(X, Y), Y) sum(X) >? fold(/\x./\y.add(x, y), 0, X) prod(X) >? fold(/\x./\y.mul(x, y), s(0), X) We use a recursive path ordering as defined in [Kop12, Chapter 5]. popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Higher Order Rewriting Union Beta