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C_Integer pair #487095105
details
property
value
status
complete
benchmark
2Nested_false-termination.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n150.star.cs.uiowa.edu
space
Ton_Chanh_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
7.03623 seconds
cpu usage
24.338
user time
22.9111
system time
1.42697
max virtual memory
2.210668E7
max residence set size
1615992.0
stage attributes
key
value
starexec-result
NO
output
NO proof of /export/starexec/sandbox/benchmark/theBenchmark.c # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given C Problem could be disproven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) IRS2T2 [EQUIVALENT, 0 ms] (4) T2IntSys (5) T2 Underapproximation [COMPLETE, 1888 ms] (6) T2IntSys (7) T2 [COMPLETE, 1254 ms] (8) NO ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(x, y) -> f2(x_1, y) :|: TRUE f2(x1, x2) -> f3(x1, x3) :|: TRUE f4(x4, x5) -> f5(arith, x5) :|: TRUE && arith = x4 + x5 f5(x14, x15) -> f6(x14, x16) :|: TRUE && x16 = x15 + 1 f3(x8, x9) -> f4(x8, x9) :|: x8 >= 0 f6(x10, x11) -> f3(x10, x11) :|: TRUE f3(x12, x13) -> f7(x12, x13) :|: x12 < 0 Start term: f1(x, y) ---------------------------------------- (3) IRS2T2 (EQUIVALENT) Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs: (f1_2,1) (f2_2,2) (f3_2,3) (f4_2,4) (f5_2,5) (f6_2,6) (f7_2,7) ---------------------------------------- (4) Obligation: START: 1; FROM: 1; oldX0 := x0; oldX1 := x1; oldX2 := nondet(); assume(0 = 0); x0 := oldX2; x1 := oldX1; TO: 2; FROM: 2; oldX0 := x0; oldX1 := x1; oldX2 := nondet(); assume(0 = 0); x0 := oldX0; x1 := oldX2; TO: 3; FROM: 4; oldX0 := x0; oldX1 := x1; oldX2 := -(-(oldX0 + oldX1)); assume(0 = 0 && oldX2 = oldX0 + oldX1); x0 := -(-(oldX0 + oldX1)); x1 := oldX1; TO: 5; FROM: 5; oldX0 := x0; oldX1 := x1; oldX2 := -(-(oldX1 + 1)); assume(0 = 0 && oldX2 = oldX1 + 1); x0 := oldX0; x1 := -(-(oldX1 + 1)); TO: 6; FROM: 3; oldX0 := x0; oldX1 := x1; assume(oldX0 >= 0);
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