details

property	value
status	complete
benchmark	PastaC7.c
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	Stroeder_15

run statistics

property	value
solver	AProVE
configuration	c
runtime (wallclock)	2.07989 seconds
cpu usage	5.17233
user time	4.89655
system time	0.27578
max virtual memory	1.8842056E7
max residence set size	402488.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.c # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 53 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 24 ms] (6) IntTRS (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IntTRS (9) PolynomialOrderProcessor [EQUIVALENT, 2 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox2/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(i, j, k, t) -> f2(x_1, j, k, t) :|: TRUE f2(x, x1, x2, x3) -> f3(x, x4, x2, x3) :|: TRUE f3(x5, x6, x7, x8) -> f4(x5, x6, x9, x8) :|: TRUE f5(x10, x11, x12, x13) -> f6(x11, x11, x12, x13) :|: TRUE f6(x14, x15, x16, x17) -> f7(x14, arith, x16, x17) :|: TRUE && arith = x14 + 1 f7(x34, x35, x36, x37) -> f8(x34, x35, x38, x37) :|: TRUE && x38 = x36 - 1 f4(x22, x23, x24, x25) -> f5(x22, x23, x24, x25) :|: x22 <= 100 && x23 <= x24 f8(x26, x27, x28, x29) -> f4(x26, x27, x28, x29) :|: TRUE f4(x30, x31, x32, x33) -> f9(x30, x31, x32, x33) :|: x30 > 100 f4(x39, x40, x41, x42) -> f9(x39, x40, x41, x42) :|: x40 > x41 Start term: f1(i, j, k, t) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f4(x22, x23, x24, x25) -> f5(x22, x23, x24, x25) :|: x22 <= 100 && x23 <= x24 f8(x26, x27, x28, x29) -> f4(x26, x27, x28, x29) :|: TRUE f7(x34, x35, x36, x37) -> f8(x34, x35, x38, x37) :|: TRUE && x38 = x36 - 1 f6(x14, x15, x16, x17) -> f7(x14, arith, x16, x17) :|: TRUE && arith = x14 + 1 f5(x10, x11, x12, x13) -> f6(x11, x11, x12, x13) :|: TRUE ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f6(x14:0, x15:0, x16:0, x17:0) -> f6(x14:0 + 1, x14:0 + 1, x16:0 - 1, x17:0) :|: x14:0 < 101 && x16:0 - 1 >= x14:0 + 1 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f6(x1, x2, x3, x4) -> f6(x1, x3) ---------------------------------------- (8) Obligation: Rules: f6(x14:0, x16:0) -> f6(x14:0 + 1, x16:0 - 1) :|: x14:0 < 101 && x16:0 - 1 >= x14:0 + 1 ---------------------------------------- (9) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [f6(x, x1)] = 100 - x The following rules are decreasing: f6(x14:0, x16:0) -> f6(x14:0 + 1, x16:0 - 1) :|: x14:0 < 101 && x16:0 - 1 >= x14:0 + 1 The following rules are bounded: f6(x14:0, x16:0) -> f6(x14:0 + 1, x16:0 - 1) :|: x14:0 < 101 && x16:0 - 1 >= x14:0 + 1 ---------------------------------------- popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to C_Integer