details

property	value
status	complete
benchmark	sum.pl
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n140.star.cs.uiowa.edu
space	talp_apt

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.72057 seconds
cpu usage	3.86944
user time	3.68738
system time	0.182061
max virtual memory	1.8811524E7
max residence set size	281028.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.pl # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Left Termination of the query pattern sum(a,a,g) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) PiDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) PiDP (9) PiDPToQDPProof [SOUND, 0 ms] (10) QDP (11) QDPSizeChangeProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Clauses: sum(X, s(Y), s(Z)) :- sum(X, Y, Z). sum(X, 0, X). Query: sum(a,a,g) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: sum_in_3: (f,f,b) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: sum_in_aag(X, s(Y), s(Z)) -> U1_aag(X, Y, Z, sum_in_aag(X, Y, Z)) sum_in_aag(X, 0, X) -> sum_out_aag(X, 0, X) U1_aag(X, Y, Z, sum_out_aag(X, Y, Z)) -> sum_out_aag(X, s(Y), s(Z)) The argument filtering Pi contains the following mapping: sum_in_aag(x1, x2, x3) = sum_in_aag(x3) s(x1) = s(x1) U1_aag(x1, x2, x3, x4) = U1_aag(x4) sum_out_aag(x1, x2, x3) = sum_out_aag(x1, x2) Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog ---------------------------------------- (2) Obligation: Pi-finite rewrite system: The TRS R consists of the following rules: sum_in_aag(X, s(Y), s(Z)) -> U1_aag(X, Y, Z, sum_in_aag(X, Y, Z)) sum_in_aag(X, 0, X) -> sum_out_aag(X, 0, X) U1_aag(X, Y, Z, sum_out_aag(X, Y, Z)) -> sum_out_aag(X, s(Y), s(Z)) The argument filtering Pi contains the following mapping: sum_in_aag(x1, x2, x3) = sum_in_aag(x3) s(x1) = s(x1) U1_aag(x1, x2, x3, x4) = U1_aag(x4) sum_out_aag(x1, x2, x3) = sum_out_aag(x1, x2) ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem: Pi DP problem: The TRS P consists of the following rules: SUM_IN_AAG(X, s(Y), s(Z)) -> U1_AAG(X, Y, Z, sum_in_aag(X, Y, Z)) popout

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