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Logic Programming pair #487096480
details
property
value
status
complete
benchmark
slowsort-bb.pl
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n143.star.cs.uiowa.edu
space
BCGGV05
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.53936 seconds
cpu usage
6.48553
user time
6.18523
system time
0.300305
max virtual memory
1.8944424E7
max residence set size
537208.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox/benchmark/theBenchmark.pl # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Left Termination of the query pattern ss(g,g) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToDTProblemTransformerProof [SOUND, 44 ms] (2) TRIPLES (3) TriplesToPiDPProof [SOUND, 31 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) PiDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) PiDP (10) PiDPToQDPProof [EQUIVALENT, 0 ms] (11) QDP (12) QDPSizeChangeProof [EQUIVALENT, 0 ms] (13) YES (14) PiDP (15) UsableRulesProof [EQUIVALENT, 0 ms] (16) PiDP (17) PiDPToQDPProof [EQUIVALENT, 2 ms] (18) QDP (19) QDPSizeChangeProof [EQUIVALENT, 0 ms] (20) YES (21) PiDP (22) UsableRulesProof [EQUIVALENT, 0 ms] (23) PiDP (24) PiDPToQDPProof [SOUND, 0 ms] (25) QDP (26) QDPSizeChangeProof [EQUIVALENT, 0 ms] (27) YES (28) PiDP (29) UsableRulesProof [EQUIVALENT, 0 ms] (30) PiDP (31) PiDPToQDPProof [SOUND, 0 ms] (32) QDP (33) QDPSizeChangeProof [EQUIVALENT, 0 ms] (34) YES (35) PiDP (36) UsableRulesProof [EQUIVALENT, 0 ms] (37) PiDP (38) PiDPToQDPProof [SOUND, 0 ms] (39) QDP (40) QDPSizeChangeProof [EQUIVALENT, 0 ms] (41) YES ---------------------------------------- (0) Obligation: Clauses: ss(Xs, Ys) :- ','(perm(Xs, Ys), ordered(Ys)). perm([], []). perm(Xs, .(X, Ys)) :- ','(app(X1s, .(X, X2s), Xs), ','(app(X1s, X2s, Zs), perm(Zs, Ys))). app([], X, X). app(.(X, Xs), Ys, .(X, Zs)) :- app(Xs, Ys, Zs). ordered([]). ordered(.(X1, [])). ordered(.(X, .(Y, Xs))) :- ','(less(X, s(Y)), ordered(.(Y, Xs))). less(0, s(X2)). less(s(X), s(Y)) :- less(X, Y). Query: ss(g,g) ---------------------------------------- (1) PrologToDTProblemTransformerProof (SOUND) Built DT problem from termination graph DT10. { "root": 23, "program": { "directives": [], "clauses": [ [ "(ss Xs Ys)", "(',' (perm Xs Ys) (ordered Ys))" ], [ "(perm ([]) ([]))", null ], [ "(perm Xs (. X Ys))", "(',' (app X1s (. X X2s) Xs) (',' (app X1s X2s Zs) (perm Zs Ys)))" ], [ "(app ([]) X X)", null ],
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