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Logic Programming pair #487096652
details
property
value
status
complete
benchmark
palindrome.pl
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n150.star.cs.uiowa.edu
space
talp_talp
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.90742 seconds
cpu usage
4.16623
user time
3.97306
system time
0.193179
max virtual memory
1.83418E7
max residence set size
301116.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox/benchmark/theBenchmark.pl # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Left Termination of the query pattern palindrome(g) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 2 ms] (6) PiDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) PiDP (9) PiDPToQDPProof [EQUIVALENT, 0 ms] (10) QDP (11) QDPSizeChangeProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Clauses: palindrome(Xs) :- reverse(Xs, Xs). reverse(X1s, X2s) :- reverse3(X1s, [], X2s). reverse3(.(X, X1s), X2s, Ys) :- reverse3(X1s, .(X, X2s), Ys). reverse3([], Xs, Xs). Query: palindrome(g) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: palindrome_in_1: (b) reverse_in_2: (b,b) reverse3_in_3: (b,b,b) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: palindrome_in_g(Xs) -> U1_g(Xs, reverse_in_gg(Xs, Xs)) reverse_in_gg(X1s, X2s) -> U2_gg(X1s, X2s, reverse3_in_ggg(X1s, [], X2s)) reverse3_in_ggg(.(X, X1s), X2s, Ys) -> U3_ggg(X, X1s, X2s, Ys, reverse3_in_ggg(X1s, .(X, X2s), Ys)) reverse3_in_ggg([], Xs, Xs) -> reverse3_out_ggg([], Xs, Xs) U3_ggg(X, X1s, X2s, Ys, reverse3_out_ggg(X1s, .(X, X2s), Ys)) -> reverse3_out_ggg(.(X, X1s), X2s, Ys) U2_gg(X1s, X2s, reverse3_out_ggg(X1s, [], X2s)) -> reverse_out_gg(X1s, X2s) U1_g(Xs, reverse_out_gg(Xs, Xs)) -> palindrome_out_g(Xs) The argument filtering Pi contains the following mapping: palindrome_in_g(x1) = palindrome_in_g(x1) U1_g(x1, x2) = U1_g(x2) reverse_in_gg(x1, x2) = reverse_in_gg(x1, x2) U2_gg(x1, x2, x3) = U2_gg(x3) reverse3_in_ggg(x1, x2, x3) = reverse3_in_ggg(x1, x2, x3) .(x1, x2) = .(x1, x2) U3_ggg(x1, x2, x3, x4, x5) = U3_ggg(x5) [] = [] reverse3_out_ggg(x1, x2, x3) = reverse3_out_ggg reverse_out_gg(x1, x2) = reverse_out_gg palindrome_out_g(x1) = palindrome_out_g Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog ---------------------------------------- (2) Obligation: Pi-finite rewrite system: The TRS R consists of the following rules:
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