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ITS pair #487096747
details
property
value
status
complete
benchmark
neg-acqrel-succeed.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n142.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
3.63446 seconds
cpu usage
3.68397
user time
1.92759
system time
1.75638
max virtual memory
684820.0
max residence set size
8580.0
stage attributes
key
value
starexec-result
MAYBE
output
MAYBE DP problem for innermost termination. P = f10#(x1, x2, x3, x4, x5) -> f9#(x1, x2, x3, x4, x5) f9#(I0, I1, I2, I3, I4) -> f4#(0, 0, I2, rnd4, I4) [rnd4 = rnd4] f5#(I5, I6, I7, I8, I9) -> f4#(I5, 0, I7, I10, I9) [I9 <= 0 /\ y1 = 1 /\ I10 = I10] f5#(I11, I12, I13, I14, I15) -> f2#(I11, I12, I13, I14, -1 + I15) [1 <= I15] f8#(I16, I17, I18, I19, I20) -> f3#(I16, I17, I18, I19, I20) f3#(I21, I22, I23, I24, I25) -> f8#(I21, I22, I23, I24, I25) f2#(I31, I32, I33, I34, I35) -> f5#(I31, I32, I33, I34, I35) f4#(I36, I37, I38, I39, I40) -> f1#(I36, I37, I38, I39, I40) f1#(I41, I42, I43, I44, I45) -> f3#(I41, I42, I43, I44, I45) [1 <= I44] f1#(I46, I47, I48, I49, I50) -> f2#(0, I47, rnd3, I49, rnd5) [I49 <= 0 /\ I51 = 1 /\ rnd3 = rnd3 /\ rnd5 = rnd3] R = f10(x1, x2, x3, x4, x5) -> f9(x1, x2, x3, x4, x5) f9(I0, I1, I2, I3, I4) -> f4(0, 0, I2, rnd4, I4) [rnd4 = rnd4] f5(I5, I6, I7, I8, I9) -> f4(I5, 0, I7, I10, I9) [I9 <= 0 /\ y1 = 1 /\ I10 = I10] f5(I11, I12, I13, I14, I15) -> f2(I11, I12, I13, I14, -1 + I15) [1 <= I15] f8(I16, I17, I18, I19, I20) -> f3(I16, I17, I18, I19, I20) f3(I21, I22, I23, I24, I25) -> f8(I21, I22, I23, I24, I25) f6(I26, I27, I28, I29, I30) -> f7(I26, I27, I28, I29, I30) f2(I31, I32, I33, I34, I35) -> f5(I31, I32, I33, I34, I35) f4(I36, I37, I38, I39, I40) -> f1(I36, I37, I38, I39, I40) f1(I41, I42, I43, I44, I45) -> f3(I41, I42, I43, I44, I45) [1 <= I44] f1(I46, I47, I48, I49, I50) -> f2(0, I47, rnd3, I49, rnd5) [I49 <= 0 /\ I51 = 1 /\ rnd3 = rnd3 /\ rnd5 = rnd3] The dependency graph for this problem is: 0 -> 1 1 -> 7 2 -> 7 3 -> 6 4 -> 5 5 -> 4 6 -> 2, 3 7 -> 8, 9 8 -> 5 9 -> 6 Where: 0) f10#(x1, x2, x3, x4, x5) -> f9#(x1, x2, x3, x4, x5) 1) f9#(I0, I1, I2, I3, I4) -> f4#(0, 0, I2, rnd4, I4) [rnd4 = rnd4] 2) f5#(I5, I6, I7, I8, I9) -> f4#(I5, 0, I7, I10, I9) [I9 <= 0 /\ y1 = 1 /\ I10 = I10] 3) f5#(I11, I12, I13, I14, I15) -> f2#(I11, I12, I13, I14, -1 + I15) [1 <= I15] 4) f8#(I16, I17, I18, I19, I20) -> f3#(I16, I17, I18, I19, I20) 5) f3#(I21, I22, I23, I24, I25) -> f8#(I21, I22, I23, I24, I25) 6) f2#(I31, I32, I33, I34, I35) -> f5#(I31, I32, I33, I34, I35) 7) f4#(I36, I37, I38, I39, I40) -> f1#(I36, I37, I38, I39, I40) 8) f1#(I41, I42, I43, I44, I45) -> f3#(I41, I42, I43, I44, I45) [1 <= I44] 9) f1#(I46, I47, I48, I49, I50) -> f2#(0, I47, rnd3, I49, rnd5) [I49 <= 0 /\ I51 = 1 /\ rnd3 = rnd3 /\ rnd5 = rnd3] We have the following SCCs. { 2, 3, 6, 7, 9 } { 4, 5 } DP problem for innermost termination. P = f8#(I16, I17, I18, I19, I20) -> f3#(I16, I17, I18, I19, I20) f3#(I21, I22, I23, I24, I25) -> f8#(I21, I22, I23, I24, I25) R = f10(x1, x2, x3, x4, x5) -> f9(x1, x2, x3, x4, x5) f9(I0, I1, I2, I3, I4) -> f4(0, 0, I2, rnd4, I4) [rnd4 = rnd4] f5(I5, I6, I7, I8, I9) -> f4(I5, 0, I7, I10, I9) [I9 <= 0 /\ y1 = 1 /\ I10 = I10] f5(I11, I12, I13, I14, I15) -> f2(I11, I12, I13, I14, -1 + I15) [1 <= I15] f8(I16, I17, I18, I19, I20) -> f3(I16, I17, I18, I19, I20) f3(I21, I22, I23, I24, I25) -> f8(I21, I22, I23, I24, I25) f6(I26, I27, I28, I29, I30) -> f7(I26, I27, I28, I29, I30) f2(I31, I32, I33, I34, I35) -> f5(I31, I32, I33, I34, I35) f4(I36, I37, I38, I39, I40) -> f1(I36, I37, I38, I39, I40) f1(I41, I42, I43, I44, I45) -> f3(I41, I42, I43, I44, I45) [1 <= I44] f1(I46, I47, I48, I49, I50) -> f2(0, I47, rnd3, I49, rnd5) [I49 <= 0 /\ I51 = 1 /\ rnd3 = rnd3 /\ rnd5 = rnd3]
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