details

property	value
status	complete
benchmark	janne_complex.t2_fixed.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n137.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	66.9581 seconds
cpu usage	67.2003
user time	36.3093
system time	30.8911
max virtual memory	796616.0
max residence set size	16896.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) f9#(I0, I1, I2, I3, I4, I5) -> f4#(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] f5#(I6, I7, I8, I9, I10, I11) -> f8#(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5#(I12, I13, I14, I15, I16, I17) -> f4#(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8#(I25, I26, I27, I28, I29, I30) -> f7#(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7#(I31, I32, I33, I34, I35, I36) -> f6#(I31, I32, I33, I34, I35, I36) [10 <= I34] f7#(I37, I38, I39, I40, I41, I42) -> f3#(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6#(I43, I44, I45, I46, I47, I48) -> f3#(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6#(I49, I50, I51, I52, I53, I54) -> f3#(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3#(I55, I56, I57, I58, I59, I60) -> f5#(I55, I56, I57, I58, I59, I60) f4#(I61, I62, I63, I64, I65, I66) -> f1#(I61, I62, I63, I64, I65, I66) f1#(I67, I68, I69, I70, I71, I72) -> f3#(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] R = f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) f9(I0, I1, I2, I3, I4, I5) -> f4(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] f5(I6, I7, I8, I9, I10, I11) -> f8(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5(I12, I13, I14, I15, I16, I17) -> f4(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8(I18, I19, I20, I21, I22, I23) -> f7(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8(I25, I26, I27, I28, I29, I30) -> f7(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7(I31, I32, I33, I34, I35, I36) -> f6(I31, I32, I33, I34, I35, I36) [10 <= I34] f7(I37, I38, I39, I40, I41, I42) -> f3(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6(I43, I44, I45, I46, I47, I48) -> f3(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6(I49, I50, I51, I52, I53, I54) -> f3(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3(I55, I56, I57, I58, I59, I60) -> f5(I55, I56, I57, I58, I59, I60) f4(I61, I62, I63, I64, I65, I66) -> f1(I61, I62, I63, I64, I65, I66) f1(I67, I68, I69, I70, I71, I72) -> f3(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] f1(I73, I74, I75, I76, I77, I78) -> f2(I73, I74, rnd3, I76, I77, 1) [rnd3 = 1 /\ 30 <= I73] The dependency graph for this problem is: 0 -> 1 1 -> 11 2 -> 4, 5 3 -> 11 4 -> 6, 7 5 -> 7 6 -> 8, 9 7 -> 10 8 -> 10 9 -> 10 10 -> 2, 3 11 -> 12 12 -> 10 Where: 0) f10#(x1, x2, x3, x4, x5, x6) -> f9#(x1, x2, x3, x4, x5, x6) 1) f9#(I0, I1, I2, I3, I4, I5) -> f4#(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] 2) f5#(I6, I7, I8, I9, I10, I11) -> f8#(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] 3) f5#(I12, I13, I14, I15, I16, I17) -> f4#(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] 4) f8#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] 5) f8#(I25, I26, I27, I28, I29, I30) -> f7#(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] 6) f7#(I31, I32, I33, I34, I35, I36) -> f6#(I31, I32, I33, I34, I35, I36) [10 <= I34] 7) f7#(I37, I38, I39, I40, I41, I42) -> f3#(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] 8) f6#(I43, I44, I45, I46, I47, I48) -> f3#(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] 9) f6#(I49, I50, I51, I52, I53, I54) -> f3#(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] 10) f3#(I55, I56, I57, I58, I59, I60) -> f5#(I55, I56, I57, I58, I59, I60) 11) f4#(I61, I62, I63, I64, I65, I66) -> f1#(I61, I62, I63, I64, I65, I66) 12) f1#(I67, I68, I69, I70, I71, I72) -> f3#(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] We have the following SCCs. { 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 } DP problem for innermost termination. P = f5#(I6, I7, I8, I9, I10, I11) -> f8#(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5#(I12, I13, I14, I15, I16, I17) -> f4#(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8#(I25, I26, I27, I28, I29, I30) -> f7#(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7#(I31, I32, I33, I34, I35, I36) -> f6#(I31, I32, I33, I34, I35, I36) [10 <= I34] f7#(I37, I38, I39, I40, I41, I42) -> f3#(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6#(I43, I44, I45, I46, I47, I48) -> f3#(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6#(I49, I50, I51, I52, I53, I54) -> f3#(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3#(I55, I56, I57, I58, I59, I60) -> f5#(I55, I56, I57, I58, I59, I60) f4#(I61, I62, I63, I64, I65, I66) -> f1#(I61, I62, I63, I64, I65, I66) f1#(I67, I68, I69, I70, I71, I72) -> f3#(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] R = f10(x1, x2, x3, x4, x5, x6) -> f9(x1, x2, x3, x4, x5, x6) f9(I0, I1, I2, I3, I4, I5) -> f4(rnd1, 1, 0, rnd4, 1, I5) [rnd4 = 1 /\ rnd1 = 1] f5(I6, I7, I8, I9, I10, I11) -> f8(I6, I7, I8, I9, I10, I11) [1 + I9 <= I6] f5(I12, I13, I14, I15, I16, I17) -> f4(2 + I12, I13, I14, -10 + I15, I16, I17) [I12 <= I15] f8(I18, I19, I20, I21, I22, I23) -> f7(I18, I19, I20, I24, I22, I23) [I24 = I24 /\ 6 <= I21] f8(I25, I26, I27, I28, I29, I30) -> f7(I25, I26, I27, 2 + I28, I29, I30) [I28 <= 5] f7(I31, I32, I33, I34, I35, I36) -> f6(I31, I32, I33, I34, I35, I36) [10 <= I34] f7(I37, I38, I39, I40, I41, I42) -> f3(1 + I37, I38, I39, I40, I41, I42) [1 + I40 <= 10] f6(I43, I44, I45, I46, I47, I48) -> f3(10 + I43, I44, I45, I46, I47, I48) [I46 <= 12] f6(I49, I50, I51, I52, I53, I54) -> f3(1 + I49, I50, I51, I52, I53, I54) [13 <= I52] f3(I55, I56, I57, I58, I59, I60) -> f5(I55, I56, I57, I58, I59, I60) f4(I61, I62, I63, I64, I65, I66) -> f1(I61, I62, I63, I64, I65, I66) f1(I67, I68, I69, I70, I71, I72) -> f3(I67, I68, I69, I70, I71, I72) [1 + I67 <= 30] f1(I73, I74, I75, I76, I77, I78) -> f2(I73, I74, rnd3, I76, I77, 1) [rnd3 = 1 /\ 30 <= I73] We use the extended value criterion with the projection function NU: NU[f1#(x0,x1,x2,x3,x4,x5)] = -x0 + 29 NU[f3#(x0,x1,x2,x3,x4,x5)] = -x0 + 28 NU[f6#(x0,x1,x2,x3,x4,x5)] = -x0 + 27 NU[f7#(x0,x1,x2,x3,x4,x5)] = -x0 + 27 NU[f4#(x0,x1,x2,x3,x4,x5)] = -x0 + 29 popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to ITS