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ITS pair #487097002
details
property
value
status
complete
benchmark
st88.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n148.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
14.1402 seconds
cpu usage
14.3091
user time
7.5281
system time
6.781
max virtual memory
623808.0
max residence set size
12452.0
stage attributes
key
value
starexec-result
MAYBE
output
MAYBE DP problem for innermost termination. P = f14#(x1, x2, x3) -> f13#(x1, x2, x3) f13#(I0, I1, I2) -> f4#(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1] f3#(I3, I4, I5) -> f5#(1 + I3, I4, I5) [I3 <= I4] f3#(I6, I7, I8) -> f5#(1 + I6, I7, I8) [1 + I7 <= I6] f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 + I11 <= 0] f2#(I12, I13, I14) -> f3#(I12, I13, I14) [1 <= I14] f2#(I15, I16, I17) -> f6#(I15, I16, I17) [0 <= I17 /\ I17 <= 0] f7#(I18, I19, I20) -> f6#(-1 + I18, I19, I20) [3 <= I18] f7#(I21, I22, I23) -> f4#(I21, I22, I23) [I21 <= 2] f12#(I24, I25, I26) -> f11#(I24, I25, I26) f11#(I27, I28, I29) -> f12#(I27, I28, I29) f10#(I30, I31, I32) -> f11#(I30, I31, I32) f6#(I36, I37, I38) -> f7#(I36, I37, I38) f5#(I39, I40, I41) -> f1#(I39, I40, I41) f4#(I42, I43, I44) -> f5#(I42, I43, I44) f1#(I45, I46, I47) -> f3#(I45, I46, I47) [I45 <= I46] f1#(I48, I49, I50) -> f2#(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48] R = f14(x1, x2, x3) -> f13(x1, x2, x3) f13(I0, I1, I2) -> f4(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1] f3(I3, I4, I5) -> f5(1 + I3, I4, I5) [I3 <= I4] f3(I6, I7, I8) -> f5(1 + I6, I7, I8) [1 + I7 <= I6] f2(I9, I10, I11) -> f3(I9, I10, I11) [1 + I11 <= 0] f2(I12, I13, I14) -> f3(I12, I13, I14) [1 <= I14] f2(I15, I16, I17) -> f6(I15, I16, I17) [0 <= I17 /\ I17 <= 0] f7(I18, I19, I20) -> f6(-1 + I18, I19, I20) [3 <= I18] f7(I21, I22, I23) -> f4(I21, I22, I23) [I21 <= 2] f12(I24, I25, I26) -> f11(I24, I25, I26) f11(I27, I28, I29) -> f12(I27, I28, I29) f10(I30, I31, I32) -> f11(I30, I31, I32) f8(I33, I34, I35) -> f9(I33, I34, I35) f6(I36, I37, I38) -> f7(I36, I37, I38) f5(I39, I40, I41) -> f1(I39, I40, I41) f4(I42, I43, I44) -> f5(I42, I43, I44) f1(I45, I46, I47) -> f3(I45, I46, I47) [I45 <= I46] f1(I48, I49, I50) -> f2(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48] The dependency graph for this problem is: 0 -> 1 1 -> 14 2 -> 13 3 -> 13 4 -> 2, 3 5 -> 2, 3 6 -> 12 7 -> 12 8 -> 14 9 -> 10 10 -> 9 11 -> 10 12 -> 7, 8 13 -> 15, 16 14 -> 13 15 -> 2 16 -> 4, 5, 6 Where: 0) f14#(x1, x2, x3) -> f13#(x1, x2, x3) 1) f13#(I0, I1, I2) -> f4#(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1] 2) f3#(I3, I4, I5) -> f5#(1 + I3, I4, I5) [I3 <= I4] 3) f3#(I6, I7, I8) -> f5#(1 + I6, I7, I8) [1 + I7 <= I6] 4) f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 + I11 <= 0] 5) f2#(I12, I13, I14) -> f3#(I12, I13, I14) [1 <= I14] 6) f2#(I15, I16, I17) -> f6#(I15, I16, I17) [0 <= I17 /\ I17 <= 0] 7) f7#(I18, I19, I20) -> f6#(-1 + I18, I19, I20) [3 <= I18] 8) f7#(I21, I22, I23) -> f4#(I21, I22, I23) [I21 <= 2] 9) f12#(I24, I25, I26) -> f11#(I24, I25, I26) 10) f11#(I27, I28, I29) -> f12#(I27, I28, I29) 11) f10#(I30, I31, I32) -> f11#(I30, I31, I32) 12) f6#(I36, I37, I38) -> f7#(I36, I37, I38) 13) f5#(I39, I40, I41) -> f1#(I39, I40, I41) 14) f4#(I42, I43, I44) -> f5#(I42, I43, I44) 15) f1#(I45, I46, I47) -> f3#(I45, I46, I47) [I45 <= I46] 16) f1#(I48, I49, I50) -> f2#(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48] We have the following SCCs. { 9, 10 } { 2, 3, 4, 5, 6, 7, 8, 12, 13, 14, 15, 16 } DP problem for innermost termination. P = f3#(I3, I4, I5) -> f5#(1 + I3, I4, I5) [I3 <= I4] f3#(I6, I7, I8) -> f5#(1 + I6, I7, I8) [1 + I7 <= I6] f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 + I11 <= 0] f2#(I12, I13, I14) -> f3#(I12, I13, I14) [1 <= I14] f2#(I15, I16, I17) -> f6#(I15, I16, I17) [0 <= I17 /\ I17 <= 0] f7#(I18, I19, I20) -> f6#(-1 + I18, I19, I20) [3 <= I18] f7#(I21, I22, I23) -> f4#(I21, I22, I23) [I21 <= 2] f6#(I36, I37, I38) -> f7#(I36, I37, I38) f5#(I39, I40, I41) -> f1#(I39, I40, I41) f4#(I42, I43, I44) -> f5#(I42, I43, I44) f1#(I45, I46, I47) -> f3#(I45, I46, I47) [I45 <= I46] f1#(I48, I49, I50) -> f2#(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48] R = f14(x1, x2, x3) -> f13(x1, x2, x3) f13(I0, I1, I2) -> f4(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1] f3(I3, I4, I5) -> f5(1 + I3, I4, I5) [I3 <= I4]
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