details

property	value
status	complete
benchmark	simple_test2.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	1.49192 seconds
cpu usage	1.51085
user time	0.794492
system time	0.716358
max virtual memory	721248.0
max residence set size	8572.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = f4#(x1, x2) -> f3#(x1, x2) f3#(I0, I1) -> f1#(0, -1 + I1) [y1 = 0 /\ y2 = 1] f2#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f2#(I4, I5) [0 <= I4] R = f4(x1, x2) -> f3(x1, x2) f3(I0, I1) -> f1(0, -1 + I1) [y1 = 0 /\ y2 = 1] f2(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(I4, I5) [0 <= I4] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f4#(x1, x2) -> f3#(x1, x2) 1) f3#(I0, I1) -> f1#(0, -1 + I1) [y1 = 0 /\ y2 = 1] 2) f2#(I2, I3) -> f1#(I2, I3) 3) f1#(I4, I5) -> f2#(I4, I5) [0 <= I4] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f2#(I4, I5) [0 <= I4] R = f4(x1, x2) -> f3(x1, x2) f3(I0, I1) -> f1(0, -1 + I1) [y1 = 0 /\ y2 = 1] f2(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(I4, I5) [0 <= I4] popout

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job log

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actions

all output return to ITS