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ITS pair #487097482
details
property
value
status
complete
benchmark
constants.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n148.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
15.8071 seconds
cpu usage
16.0467
user time
8.40928
system time
7.63745
max virtual memory
704564.0
max residence set size
11140.0
stage attributes
key
value
starexec-result
YES
output
YES DP problem for innermost termination. P = f9#(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f8#(x1, x2, x3, x4, x5, x6, x7, x8, x9) f8#(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f4#(I0, I1, I2, I3, I4, I3, 0, 0, I8) f2#(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4#(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) f4#(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f2#(rnd1, I26, I20, I21, I22, I23, I24, rnd8, I26) [I25 <= 0 /\ 0 <= I25 /\ 0 <= -1 + I23 - I24 /\ y1 = I26 /\ rnd8 = y1 /\ rnd1 = rnd1] f4#(I47, I48, I49, I50, I51, I52, I53, I54, I55) -> f5#(I47, I48, I49, I50, I51, I52, I53, I54, I55) [I51 = I51] f3#(I56, I57, I58, I59, I60, I61, I62, I63, I64) -> f4#(I65, I64, I58, I59, I60, I61, 1 + I62, I66, I64) [I67 = I64 /\ I66 = I67 /\ I65 = I65] f1#(I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I77, I76, I70, I71, I72, I73, I74, I78, I76) [I79 = I76 /\ I78 = I79 /\ I77 = I77] R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f4(I0, I1, I2, I3, I4, I3, 0, 0, I8) f2(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) f4(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f2(rnd1, I26, I20, I21, I22, I23, I24, rnd8, I26) [I25 <= 0 /\ 0 <= I25 /\ 0 <= -1 + I23 - I24 /\ y1 = I26 /\ rnd8 = y1 /\ rnd1 = rnd1] f4(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f7(I36, I28, I34, I30, I31, I32, I33, I34, I35) [I36 = I34 /\ I32 - I33 <= 0 /\ 0 <= I34 /\ I34 <= 0] f5(I37, I38, I39, I40, I41, I42, I43, I44, I45) -> f6(I46, I38, I44, I40, I41, I42, I43, I44, I45) [I46 = I44] f4(I47, I48, I49, I50, I51, I52, I53, I54, I55) -> f5(I47, I48, I49, I50, I51, I52, I53, I54, I55) [I51 = I51] f3(I56, I57, I58, I59, I60, I61, I62, I63, I64) -> f4(I65, I64, I58, I59, I60, I61, 1 + I62, I66, I64) [I67 = I64 /\ I66 = I67 /\ I65 = I65] f1(I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(I77, I76, I70, I71, I72, I73, I74, I78, I76) [I79 = I76 /\ I78 = I79 /\ I77 = I77] The dependency graph for this problem is: 0 -> 1 1 -> 3, 4 2 -> 3, 4 3 -> 2 4 -> 5 -> 3, 4 6 -> 2 Where: 0) f9#(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f8#(x1, x2, x3, x4, x5, x6, x7, x8, x9) 1) f8#(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f4#(I0, I1, I2, I3, I4, I3, 0, 0, I8) 2) f2#(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4#(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) 3) f4#(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f2#(rnd1, I26, I20, I21, I22, I23, I24, rnd8, I26) [I25 <= 0 /\ 0 <= I25 /\ 0 <= -1 + I23 - I24 /\ y1 = I26 /\ rnd8 = y1 /\ rnd1 = rnd1] 4) f4#(I47, I48, I49, I50, I51, I52, I53, I54, I55) -> f5#(I47, I48, I49, I50, I51, I52, I53, I54, I55) [I51 = I51] 5) f3#(I56, I57, I58, I59, I60, I61, I62, I63, I64) -> f4#(I65, I64, I58, I59, I60, I61, 1 + I62, I66, I64) [I67 = I64 /\ I66 = I67 /\ I65 = I65] 6) f1#(I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2#(I77, I76, I70, I71, I72, I73, I74, I78, I76) [I79 = I76 /\ I78 = I79 /\ I77 = I77] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4#(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) f4#(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f2#(rnd1, I26, I20, I21, I22, I23, I24, rnd8, I26) [I25 <= 0 /\ 0 <= I25 /\ 0 <= -1 + I23 - I24 /\ y1 = I26 /\ rnd8 = y1 /\ rnd1 = rnd1] R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f4(I0, I1, I2, I3, I4, I3, 0, 0, I8) f2(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) f4(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f2(rnd1, I26, I20, I21, I22, I23, I24, rnd8, I26) [I25 <= 0 /\ 0 <= I25 /\ 0 <= -1 + I23 - I24 /\ y1 = I26 /\ rnd8 = y1 /\ rnd1 = rnd1] f4(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f7(I36, I28, I34, I30, I31, I32, I33, I34, I35) [I36 = I34 /\ I32 - I33 <= 0 /\ 0 <= I34 /\ I34 <= 0] f5(I37, I38, I39, I40, I41, I42, I43, I44, I45) -> f6(I46, I38, I44, I40, I41, I42, I43, I44, I45) [I46 = I44] f4(I47, I48, I49, I50, I51, I52, I53, I54, I55) -> f5(I47, I48, I49, I50, I51, I52, I53, I54, I55) [I51 = I51] f3(I56, I57, I58, I59, I60, I61, I62, I63, I64) -> f4(I65, I64, I58, I59, I60, I61, 1 + I62, I66, I64) [I67 = I64 /\ I66 = I67 /\ I65 = I65] f1(I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(I77, I76, I70, I71, I72, I73, I74, I78, I76) [I79 = I76 /\ I78 = I79 /\ I77 = I77] We use the reverse value criterion with the projection function NU: NU[f4#(z1,z2,z3,z4,z5,z6,z7,z8,z9)] = -1 + z6 - z7 + -1 * 0 NU[f2#(z1,z2,z3,z4,z5,z6,z7,z8,z9)] = -1 + z6 - (1 + z7) + -1 * 0 This gives the following inequalities: ==> -1 + I14 - (1 + I15) + -1 * 0 >= -1 + I14 - (1 + I15) + -1 * 0 I25 <= 0 /\ 0 <= I25 /\ 0 <= -1 + I23 - I24 /\ y1 = I26 /\ rnd8 = y1 /\ rnd1 = rnd1 ==> -1 + I23 - I24 + -1 * 0 > -1 + I23 - (1 + I24) + -1 * 0 with -1 + I23 - I24 + -1 * 0 >= 0 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f2#(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4#(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) R = f9(x1, x2, x3, x4, x5, x6, x7, x8, x9) -> f8(x1, x2, x3, x4, x5, x6, x7, x8, x9) f8(I0, I1, I2, I3, I4, I5, I6, I7, I8) -> f4(I0, I1, I2, I3, I4, I3, 0, 0, I8) f2(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) f4(I18, I19, I20, I21, I22, I23, I24, I25, I26) -> f2(rnd1, I26, I20, I21, I22, I23, I24, rnd8, I26) [I25 <= 0 /\ 0 <= I25 /\ 0 <= -1 + I23 - I24 /\ y1 = I26 /\ rnd8 = y1 /\ rnd1 = rnd1] f4(I27, I28, I29, I30, I31, I32, I33, I34, I35) -> f7(I36, I28, I34, I30, I31, I32, I33, I34, I35) [I36 = I34 /\ I32 - I33 <= 0 /\ 0 <= I34 /\ I34 <= 0] f5(I37, I38, I39, I40, I41, I42, I43, I44, I45) -> f6(I46, I38, I44, I40, I41, I42, I43, I44, I45) [I46 = I44] f4(I47, I48, I49, I50, I51, I52, I53, I54, I55) -> f5(I47, I48, I49, I50, I51, I52, I53, I54, I55) [I51 = I51] f3(I56, I57, I58, I59, I60, I61, I62, I63, I64) -> f4(I65, I64, I58, I59, I60, I61, 1 + I62, I66, I64) [I67 = I64 /\ I66 = I67 /\ I65 = I65] f1(I68, I69, I70, I71, I72, I73, I74, I75, I76) -> f2(I77, I76, I70, I71, I72, I73, I74, I78, I76) [I79 = I76 /\ I78 = I79 /\ I77 = I77] The dependency graph for this problem is: 2 -> Where: 2) f2#(I9, I10, I11, I12, I13, I14, I15, I16, I17) -> f4#(I9, I10, I11, I12, I13, I14, 1 + I15, I16, I17) We have the following SCCs.
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