details

property	value
status	complete
benchmark	n-18.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n150.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	1.54239 seconds
cpu usage	1.54736
user time	0.811393
system time	0.735963
max virtual memory	717900.0
max residence set size	8572.0

stage attributes

key	value
starexec-result	MAYBE

output

MAYBE DP problem for innermost termination. P = f5#(x1, x2) -> f1#(x1, x2) f3#(I2, I3) -> f2#(I2, I3) f2#(I4, I5) -> f3#(I4, -1 + I5) [-1 + I5 <= 0] f1#(I6, I7) -> f2#(I6, I7) R = f5(x1, x2) -> f1(x1, x2) f2(I0, I1) -> f4(rnd1, -1 + I1) [rnd1 = rnd1 /\ 0 <= -1 + -1 + I1] f3(I2, I3) -> f2(I2, I3) f2(I4, I5) -> f3(I4, -1 + I5) [-1 + I5 <= 0] f1(I6, I7) -> f2(I6, I7) The dependency graph for this problem is: 0 -> 3 1 -> 2 2 -> 1 3 -> 2 Where: 0) f5#(x1, x2) -> f1#(x1, x2) 1) f3#(I2, I3) -> f2#(I2, I3) 2) f2#(I4, I5) -> f3#(I4, -1 + I5) [-1 + I5 <= 0] 3) f1#(I6, I7) -> f2#(I6, I7) We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = f3#(I2, I3) -> f2#(I2, I3) f2#(I4, I5) -> f3#(I4, -1 + I5) [-1 + I5 <= 0] R = f5(x1, x2) -> f1(x1, x2) f2(I0, I1) -> f4(rnd1, -1 + I1) [rnd1 = rnd1 /\ 0 <= -1 + -1 + I1] f3(I2, I3) -> f2(I2, I3) f2(I4, I5) -> f3(I4, -1 + I5) [-1 + I5 <= 0] f1(I6, I7) -> f2(I6, I7) popout

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job log

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actions

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