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ITS pair #487098007
details
property
value
status
complete
benchmark
java_Double2.c.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n146.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
14.2942 seconds
cpu usage
14.5269
user time
7.71588
system time
6.81098
max virtual memory
720288.0
max residence set size
10764.0
stage attributes
key
value
starexec-result
YES
output
YES DP problem for innermost termination. P = f9#(x1, x2, x3, x4, x5, x6) -> f7#(x1, x2, x3, x4, x5, x6) f7#(I0, I1, I2, I3, I4, I5) -> f5#(I0, I1, I2, I3, I4, I5) f7#(I6, I7, I8, I9, I10, I11) -> f6#(I6, I7, I8, I9, I10, I11) f7#(I12, I13, I14, I15, I16, I17) -> f4#(I12, I13, I14, I15, I16, I17) f7#(I18, I19, I20, I21, I22, I23) -> f3#(I18, I19, I20, I21, I22, I23) f7#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, I27, I28, I29) f5#(I48, I49, I50, I51, I52, I53) -> f6#(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6#(I56, I57, I58, I59, I60, I61) -> f4#(I60, I61, I58, I59, I60, -1 + I60) f4#(I62, I63, I64, I65, I66, I67) -> f3#(I66, I67, I64, I65, I66, I67) [0 <= I67] f4#(I68, I69, I70, I71, I72, I73) -> f1#(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] f3#(I74, I75, I76, I77, I78, I79) -> f5#(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3#(I82, I83, I84, I85, I86, I87) -> f4#(I86, I87, I84, I85, I86, -1 + I87) R = f9(x1, x2, x3, x4, x5, x6) -> f7(x1, x2, x3, x4, x5, x6) f7(I0, I1, I2, I3, I4, I5) -> f5(I0, I1, I2, I3, I4, I5) f7(I6, I7, I8, I9, I10, I11) -> f6(I6, I7, I8, I9, I10, I11) f7(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I16, I17) f7(I18, I19, I20, I21, I22, I23) -> f3(I18, I19, I20, I21, I22, I23) f7(I24, I25, I26, I27, I28, I29) -> f1(I24, I25, I26, I27, I28, I29) f7(I30, I31, I32, I33, I34, I35) -> f2(I30, I31, I32, I33, I34, I35) f7(I36, I37, I38, I39, I40, I41) -> f8(I36, I37, I38, I39, I40, I41) f7(I42, I43, I44, I45, I46, I47) -> f8(I46, I47, rnd3, rnd4, rnd5, rnd6) [rnd6 = rnd4 /\ rnd5 = rnd3 /\ rnd4 = rnd4 /\ rnd3 = rnd3] f5(I48, I49, I50, I51, I52, I53) -> f6(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6(I56, I57, I58, I59, I60, I61) -> f4(I60, I61, I58, I59, I60, -1 + I60) f4(I62, I63, I64, I65, I66, I67) -> f3(I66, I67, I64, I65, I66, I67) [0 <= I67] f4(I68, I69, I70, I71, I72, I73) -> f1(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] f3(I74, I75, I76, I77, I78, I79) -> f5(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3(I82, I83, I84, I85, I86, I87) -> f4(I86, I87, I84, I85, I86, -1 + I87) f1(I88, I89, I90, I91, I92, I93) -> f2(I92, I93, I94, I95, I96, I97) [I97 = I95 /\ I96 = I94 /\ I95 = I95 /\ I94 = I94] The dependency graph for this problem is: 0 -> 1, 2, 3, 4, 5 1 -> 6 2 -> 7 3 -> 8, 9 4 -> 10, 11 5 -> 6 -> 7 7 -> 8, 9 8 -> 10, 11 9 -> 10 -> 6 11 -> 8, 9 Where: 0) f9#(x1, x2, x3, x4, x5, x6) -> f7#(x1, x2, x3, x4, x5, x6) 1) f7#(I0, I1, I2, I3, I4, I5) -> f5#(I0, I1, I2, I3, I4, I5) 2) f7#(I6, I7, I8, I9, I10, I11) -> f6#(I6, I7, I8, I9, I10, I11) 3) f7#(I12, I13, I14, I15, I16, I17) -> f4#(I12, I13, I14, I15, I16, I17) 4) f7#(I18, I19, I20, I21, I22, I23) -> f3#(I18, I19, I20, I21, I22, I23) 5) f7#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, I27, I28, I29) 6) f5#(I48, I49, I50, I51, I52, I53) -> f6#(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] 7) f6#(I56, I57, I58, I59, I60, I61) -> f4#(I60, I61, I58, I59, I60, -1 + I60) 8) f4#(I62, I63, I64, I65, I66, I67) -> f3#(I66, I67, I64, I65, I66, I67) [0 <= I67] 9) f4#(I68, I69, I70, I71, I72, I73) -> f1#(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] 10) f3#(I74, I75, I76, I77, I78, I79) -> f5#(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] 11) f3#(I82, I83, I84, I85, I86, I87) -> f4#(I86, I87, I84, I85, I86, -1 + I87) We have the following SCCs. { 6, 7, 8, 10, 11 } DP problem for innermost termination. P = f5#(I48, I49, I50, I51, I52, I53) -> f6#(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6#(I56, I57, I58, I59, I60, I61) -> f4#(I60, I61, I58, I59, I60, -1 + I60) f4#(I62, I63, I64, I65, I66, I67) -> f3#(I66, I67, I64, I65, I66, I67) [0 <= I67] f3#(I74, I75, I76, I77, I78, I79) -> f5#(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3#(I82, I83, I84, I85, I86, I87) -> f4#(I86, I87, I84, I85, I86, -1 + I87) R = f9(x1, x2, x3, x4, x5, x6) -> f7(x1, x2, x3, x4, x5, x6) f7(I0, I1, I2, I3, I4, I5) -> f5(I0, I1, I2, I3, I4, I5) f7(I6, I7, I8, I9, I10, I11) -> f6(I6, I7, I8, I9, I10, I11) f7(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I16, I17) f7(I18, I19, I20, I21, I22, I23) -> f3(I18, I19, I20, I21, I22, I23) f7(I24, I25, I26, I27, I28, I29) -> f1(I24, I25, I26, I27, I28, I29) f7(I30, I31, I32, I33, I34, I35) -> f2(I30, I31, I32, I33, I34, I35) f7(I36, I37, I38, I39, I40, I41) -> f8(I36, I37, I38, I39, I40, I41) f7(I42, I43, I44, I45, I46, I47) -> f8(I46, I47, rnd3, rnd4, rnd5, rnd6) [rnd6 = rnd4 /\ rnd5 = rnd3 /\ rnd4 = rnd4 /\ rnd3 = rnd3] f5(I48, I49, I50, I51, I52, I53) -> f6(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6(I56, I57, I58, I59, I60, I61) -> f4(I60, I61, I58, I59, I60, -1 + I60) f4(I62, I63, I64, I65, I66, I67) -> f3(I66, I67, I64, I65, I66, I67) [0 <= I67] f4(I68, I69, I70, I71, I72, I73) -> f1(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] f3(I74, I75, I76, I77, I78, I79) -> f5(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3(I82, I83, I84, I85, I86, I87) -> f4(I86, I87, I84, I85, I86, -1 + I87) f1(I88, I89, I90, I91, I92, I93) -> f2(I92, I93, I94, I95, I96, I97) [I97 = I95 /\ I96 = I94 /\ I95 = I95 /\ I94 = I94] We use the extended value criterion with the projection function NU: NU[f3#(x0,x1,x2,x3,x4,x5)] = x5 NU[f4#(x0,x1,x2,x3,x4,x5)] = x5 + 1 NU[f6#(x0,x1,x2,x3,x4,x5)] = x4 NU[f5#(x0,x1,x2,x3,x4,x5)] = x4 This gives the following inequalities: I55 = I54 /\ I54 = I54 ==> I52 >= I52 ==> I60 >= (-1 + I60) + 1 0 <= I67 ==> I67 + 1 > I67 with I67 + 1 >= 0 I81 = I80 /\ I80 = I80 ==> I79 >= I79
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